Factor 6x4 – 5x2 12x2 – 10 by grouping. what is the resulting expression? (6x 5)(x2 – 2) (6x – 5)(x2 2) (6x2 5)(x2 – 2) (6x2 – 5
1 answer:
You might be interested in
The general form of a solution of the differential equation is already provided for us:
where . We now want to find a solution
such that
and
. Therefore, all we need to do is find the constants
and
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.