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luda_lava [24]
2 years ago
13

For triangle xyz , the measures of angles x,y, and Z are known. Which method should be used to start solving triangle xyz?

Mathematics
1 answer:
Kisachek [45]2 years ago
5 0

Neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

<h3>Solving trianngles using the laws of sines & cosines </h3>

The law of sines is written as

\frac{sinA}{a}=\frac{sinB}{b}= \frac{sinC}{c}

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

  1. Two angles and one side, or
  2. Two sides and a non-included angle

The law of cosines is written as

a² = b² + c² -2bc cosA, or

b² = a² + c² - 2ac cosB, or

c² = a² + b² -2ab cosC

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

  1. Three sides or
  2. Two sides and the included angle

Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.

Hence, neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

Learn more on Solving triangles using the laws of sines & cosines here: brainly.com/question/22339733

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Answer:

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to confirm this we put the values into the formula below

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