Answer:
a = 0, b = -15
Step-by-step explanation:
Given two complex number Z1=3cispi and z2=5cis(pi/2)
In polar form;
z1 = 3(cospi + isinpi)
z1 = 3(-1+i0)
z1 = -3+0i
Z2 = 5(cospi/2 + isinpi/2)
Z2 = 5(0+i)
Z2 = 0+5i
Z1*Z2 = (-3+0i)(0+5i)
Z1*Z2 = 0 - 15i +0i + 0i²
Z1*Z2 = 0-15i
comparing 0-15i with a + bi;
a = 0 and b = -15
This looks unusual but let's try it.
x+4=x+8
Let's move the x vales to the left and numbers to the right.
x-x=8-4
0=-4
Hm. This doesn't work, does it?
This equation has no solution. If you believe you typed it wrong, correct it in the comment seciton.
Ann went (1) for his distance
Answer:
C
Step-by-step explanation:
