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3 years ago

WHICH VALUE IS AN EXTRANEOUS SOLUTION X=-3X+12

Mathematics

1 answer:

Rina8888 [55]3 years ago

8 0

<span>X=-3X+12
4X = 12
X = 3

answer
X = 3</span>

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If ADAB ACBA,<br> ZD = 132° and ZC = x + 18

d1i1m1o1n [39]

Answer:

x = 114

Step-by-step explanation:

since the triangles are congruent then corresponding angles are congruent, then

∠ C = ∠ D , that is

x + 18 = 132 ( subtract 18 from both sides )

x = 114

8 0

1 year ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

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2 years ago

Question 20(Multiple Choice Worth 1 points)

kirza4 [7]

X = 4 because 1 over 24 times 4 is 4 over 24 which is converted to 1 over 6

7 0

3 years ago

Find the function rule

dybincka [34]

1/-5, because when x increases by 1, y decreases by 5

6 0

3 years ago

25POINTS!!!

irina [24]

Answer:

10.8 cm

Step-by-step explanation:

Using cosine law

g² = 7.1² + 6.7² - 2(7.1)(6.7)cos(103)

g² = 116.7018433

g = 10.80286274

5 0

3 years ago