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GuDViN [60]
2 years ago
13

In Antoine Lavoisier’s classic experiment, mercuric oxide is heated in a sealed container. The solid red powder is changed into

two products: silver liquid mercury and oxygen gas. If Lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury, how much oxygen would be released? A) 7 grams B) 16 grams Reactivate C) 32 grams D) 93 grams
SAT
1 answer:
never [62]2 years ago
8 0

Answer:

<em>A ) 7 GRAMS</em>

Explanation:

7 grams.

The sum of the reactants must equal the sum of the products.

Reactant = 100 grams

Products = 100 g mercuric oxide - 93 g mercury which equals 7 grams oxygen.

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Answer:

40 Bran Muffins

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Explanation:

Let the number of Bran muffins ordered = x

The number of Blueberry muffins ordered = 2x <em>(it is given that the number of blueberry muffins is twice the number of bran muffins)</em>

<em />

The cost of Bran muffins ordered = Number of Bran muffins * cost of 1 muffin

Cost of Bran muffins ordered = x * 2

Cost of Bran Muffins ordered = $ 2x

The cost of Blueberry muffins ordered = Number of Blueberry muffins * Cost  of 1 blueberry muffin

Cost of Blueberry muffins ordered = 2x * 4

Cost of Blueberry muffins ordered = $ 8x

Since the sum of costs of Blueberry and Bran muffins is $400

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x  = 40

Hence, the number of Bran muffins ordered is 40

we are told that the number of Blueberry muffins is twice the number of Bran muffins

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Blueberry muffins  = Bran muffins * 2

Blueberry Muffins = 40 * 2

Blueberry muffins = 80

So, the number of Blueberry muffins is 80

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