If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
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Answer:
slope = -1/12
Step-by-step explanation:
From the figure we can see that the line passes through 2 points which are
(-6,-1) and (6,-2)
Use the formula y2-y1/x2-x1
(-2-(-1))/6-(-6)
(-2+1)/6+6
-1/12
Hello from MrBillDoesMath!
Answer:
12/5
Discussion:
Note that 10 is a common denominator of both denominators:
9/5 = (9*2)/(5*2) = 18/10
- ( -6/10) = + (6/10)
So the original problem is equivalent to
18/10 + 6/10 =
(18 +6)/10 =
24/10 =
(2*12)/ (2*5) => cancelling the common factor "2"
12/5 =
2 and 2 fifths =
22/5 (though this looks like (22)/5!)
Thank you,
MrB
