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Lesechka [4]
3 years ago
11

For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

Sd(X) =\sqrt{1.2}=1.095

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=5, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The mean for the binomial distribution is given by:

E(X) =np=5*0.4=2

And the variance is given by:

Var(X) = np(1-p) =5*0.4*(1-0.4)=1.2

And the deviation is just the square root of the variance so we got:

Sd(X) =\sqrt{1.2}=1.095

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Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

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Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

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Step-by-step explanation:

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<u>     +6    + 6</u>

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