Anything between 71.5 and 72.499 recurring.
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Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer: n= 32
Jakes started with 32
Step-by-step explanation:
Let n represent the initial integer.
Step 1: take the reciprocal.
Reciprocal of n = 1/n
Step 2: double the number obtained in step 1
= 2×1/n = 2/n
Step 3: take the reciprocal of the number obtained in step 2.
Reciprocal of 2/n = n/2
Since he ended up with 16
n/2 = 16
n = 2×16 = 32
Answer:
7.87X10^3
Step-by-step explanation:
^ means to the power of
Answer:
encerio y eso
Step-by-step explanation: