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2 years ago

Conduction is the transfer of

Physics

1 answer:

mina [271]2 years ago

8 0

<em>Here is your Answer:-</em>

<em>Conduction is how heat transfers through direct contact with objects that are touching. Any time that two objects or substances touch, the hotter object passes heat to the cooler object. (That hot sand passed the heat energy right into my poor feet)!</em>

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An object is projected at 25m/s from the top of a building of height 50m. At the same instant,another object is projected from t

docker41 [41]

A) The objects have the same vertical position after 2 seconds

B) The objects have same vertical position at y = 30.4 m (but they do not collide since they have different x-position)

Explanation:

The motion of the first object along the vertical direction is a uniformly accelerated motion, so we can write its position at time t using the following equation:

$y_1(t)=h+u_1 t + \frac{1}{2}gt^2$

where:

h = 50 m is the initial height

$u_1=0$ is the initial vertical velocity (the object is projected horizontally, so the vertical velocity is zero at the beginning)

$g=-9.8 m/s^2$ is the acceleration of gravity

So, its vertical position can be rewritten as

$y_1(t)=50-4.9t^2$

The position of object 2 instead can be written as

$y_2(t)=(u_2 sin \theta)t + \frac{1}{2}gt^2$

where

$u_2 sin \theta$ is the initial vertical velocity, where

$u_2 = 50 m/s$ is the initial velocity

$\theta=30^{\circ}$ is the angle of projection

Substituting, we get:

$y_2(t)=(50)(sin 30^{\circ})t+\frac{1}{2}(-9.8)t^2=25t-4.9t^2$

The two objects collide when their vertical position is the same, so:

$y_1(t)=y_2(t)\\50-4.9t^2 = 25t-4.9t^2$

And solving for t, we find:

$50=25t\\t= 2 s$

Note that this means that the two object at t = 2 s have the same vertical position: however, this is not true for the horizontal position.

In order to find the point where they collide, we have to substitute the time of the collision that we found in part A into one of the expressions of the vertical position.

Substituting into the expression of object 2, we find:

$y_2(t) = 25t-4.9t^2=25(2.0)-4.9(2.0)^2=30.4 m$

We can verify that at the same time, the vertical position of object 1 is the same:

$y_1(t)=50-4.9t^2=50-4.9(2.0)^2=30.4 m$

This means that the two objects have the same vertical position at 30.4 m.

However, in reality, the two objects do not collide. In fact, object 1 is moving in the horizontal direction with constant velocity

$v_{1x}=25 m/s$

So its horizontal position at t = 2.0 s is

$x_1(2.0)=v_{1x}t=(25)(2.0)=50 m$

While object 2 is moving in the horizontal plane with velocity

$v_{2x}=u_2 cos \theta=(50)(cos 30^{\circ})=43.3 m/s$

So its horizontal position at t = 2.0 s is

$x_2(2.0)=v_{2x}t=(43.3)(2.0)=86.6 m$

So in reality, the two objects do not collide, if they start from the same x-position.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

7 0

3 years ago

The end of a garden hose is enclosed in a mesh sphere of radius 4 cm. If the hose delivers five liters per minute, how much wate

lana [24]

Answer

0.001339 liter

Explanation:

It is given that radius = 4 cm =0.04 m

volume of sphere $V=\frac{4}{3}\pi R^{3}$

$V=\frac{4}{3}\times 3.14\times (4\times 10^{-2})^{3}=2.674\times 10^{-4}$

It is given that hose delivers five liters per minute

So the water flows through sphere per minute is given by 5×2.674× $10^{-4}$ =0.001339 liters

6 0

3 years ago

I WILL MARK BRAINLIEST IF CORRECT!!!

Akimi4 [234]

Answer:

I'm fairly sure that the answer is "100 m/s"

Explanation:

Fnet=ma

a=Fnet/m

a=4 N / 0.040 kg

a=100 m/s

please check my work before you submit, i don't wanna let cha down :)

5 0

3 years ago

Why the life of a tornado chaser would be exciting and dangerous.

Rina8888 [55]

Explanation:

Tornado chasers are meteorologist who study and predict weather pattern. This helps them in forecasting time and location of the storm. Never the less tornado's and hurricane's can be deadly as they are powerful wind and comes with a little warning. Storm chaser are in path of storm placing scientific equipment's and hoping to get some reading and then quickly they have to retreat themselves to safe place as even a small delay could cost them their lives. Thus,we can say that life of a tornado chaser would be exciting and dangerous.

8 0

4 years ago

A neutron has a kinetic energy of 10 MeV. What size aperture would be necessary to observe diffraction effects?

Sedaia [141]

Answer: 9.33fm

Explanation:

Similarly as with a cut diffraction happens when part of the proliferating wave is cut off. This will occur for any object of request with a similar size as the wavelength of the diffracting wave.

Note, the object is moving at 14% of the speed of light. Be that as it may, the gamma factor is just 1% so taking care of the issue either relativistic or non relativistic conditions offers comparative responses.

Note: The size of the object has to be of the order of the wavelength of 10MeV. Therefore, size apperture that would be necessary to observe diffraction effect would be 9.33fm.

The calculations are in the attachment below:

8 0

3 years ago