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lesantik [10]
2 years ago
15

100 POINTS FOR ANYONE WHO CAN DO THIS!

Computers and Technology
1 answer:
Nataly [62]2 years ago
4 0

Let's check what can be modified

Before calling def we need adjective and conjunctions stored inside variables

Store them(You may change according to your choice)

\tt adjectives=("foolish","bad","long","hard")

\tt conjunctions=("and","but","for","after")

We have to make optional ,easy way ask the user to do instead of yourself .

\tt con=input("Enter\: yes\: if \:you \:want \:to \:use \:conjunctions:")

\tt adj=input("Enter\:yes\:if\:you\:want\:to\:use\: adjectives:")

If they click then we can proceed else no problem let the program run

\tt def\: conjunctionPhrase():

\quad\tt if\: con=="yes":

\quad\quad\tt return\:random.choice(conjunctions)+"\:"+nounPhrase()

\quad\tt else:

\quad\quad\tt continue

  • You may use pass also

\tt def\: adjectivePhrase():

\quad\tt if\:adj=="yes":

\quad\quad\tt return\:random.choice(adjectives)+"\:"+nounPhrase()

\quad\tt else:

\quad\quad\tt continue

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ahrayia [7]

Answer:

bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.

{

   if(root1==NULL&&root2==NULL)//both trees are null means identical.

   return true;

   if(roo1 && root2)

   {

       if(root1->data==root2->data)//condition for recursive call..

       {

           return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);

       }

   }

   else

   return false;

}

Explanation:

In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.

If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.

else returning false.

5 0
3 years ago
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arlik [135]

Answer:

see attached picture

Explanation:

An algorithm would be:

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6 0
3 years ago
Write a pseudocode method swap(aList, i, j) that interchanges the items currently in positions i and j of a list. Define the met
serious [3.7K]

Answer:

Explanation:

The following pseudocode for this method using operations of the ADT list would be the following

swap(aList, indexI, indexJ) {

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    Insert(Retrieve(indexJ, aList), indexI, aList)

    Insert(Retrieve(indexI, aList), temp_variable, aList)

}

This code basically saves the aList index of i , into a temporary Variable. Then it sets the aList index of i to the value of the element in index of j. Then it does the same for the index of j with the tem_variable. If we assume that the indexes of i and j exist, then it can crash our entire program if those indexes are missing from the list when we try to access them.

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How do you solve this.
patriot [66]
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