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ohaa [14]
3 years ago
6

What is variable declaration in java ​

Computers and Technology
2 answers:
Airida [17]3 years ago
8 0

Answer:

A variable declaration is a name given to a memory location. It is the basic unit of storage in a program.

irakobra [83]3 years ago
7 0

Answer:

Great question!

A Variable declaration is just you creating a variable to hold your data.

Some of the different types of data type are doubles, int, strings

those hold certain type of data.

Explanation:

An example is:

//I want to make a data that says Hi I am a computer programmer!

//Define the variable

String WhoIam =  "Hi I am a computer programmer!";

//I want to output the variable

System.out.print(WhoIam);

//output

Hi I am a computer programmer!

Hope this helped!

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Which is the correct description of the first act in a classical game story structure?
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Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

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For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

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For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

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