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MAVERICK [17]
2 years ago
5

Write the equation of the line passing through the points (25,3) and (-5, -3).

Mathematics
1 answer:
damaskus [11]2 years ago
6 0

The equation of the line passing through the points (25,3) and (-5, -3) in slope intercept form is y=\frac{1}{5}x-2.

The equation of a line passing through two points (x_1, y_1) and (x_2, y_2) is (y-y_1)=\frac{y_2-y_1}{x_2-x_1} (x-x_1), where \frac{y_2-y_1}{x_2-x_1} represents the slope.

Take (25,3) and (-5, -3) as (x_1, y_1) and (x_2, y_2) respectively.

Put the values in the general equation,

(y-y_1)=\frac{y_2-y_1}{x_2-x_1} (x-x_1)

(y-3)=\frac{-3-3}{-5-25} (x-25)

(y-3)=\frac{-6}{-30} (x-25)

-30(y-3)=(-6) (x-25)

-30y+90=-6x+150

-30y=-6x+150-90

-30y=-6x+60

Slope intercept form is y=mx+b, where m is the slope and b is the y-intercept

y=\frac{-6}{-30}x+\frac{60}{-30}

y=\frac{1}{5}x-2

Learn more about slope-intercept form here:

brainly.com/question/9682526?referrer=searchResults

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Answer:

{12,2}

Step-by-step explanation:

From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).

If initial point of a vector is (x_1,y_1) and terminal point is (x_2,y_2), then

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