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Anestetic [448]
3 years ago
7

What is 28% of 25 in fraction form with 100 as a denominator? For example, 8/100

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

7

70/10 or 7/1

hope this helps

Step-by-step explanation:

Dmitry [639]3 years ago
6 0
8283. ye 96 when w own with uti 78252
You might be interested in
(14 + 3/2b)-(1+8/2b)
Ray Of Light [21]

3b/2 +9

hopefully that helps

7 0
3 years ago
Read 2 more answers
What's the answer to this
Karo-lina-s [1.5K]

Answer:

m =24-8/4-2=16/2 y=4x

Step-by-step explanation:

m=24-8=16 =4-2=2

y= last number of x

8 0
3 years ago
Your company is considering a new project that will require $2,000,000 of new equipment at the start of the project. The equipme
Evgesh-ka [11]

Answer:

$385,628

Depreciation = ($2,000,000 - $250,000)/10 = $175,000

$175,000 x .39 = $68250 tax savings each period.

Across the entire project, these savings will constitute a 10 period annuity.

Pmt = 68,250, FV = 0, I = 12, N = 10, PV = 385,627.72

Step-by-step explanation:

3 0
3 years ago
A tin man has a head that is a cylinder with a cone on top. The height of the cylinder is 12 inches and the height of the cone i
boyakko [2]
First find the volume of the cylinder, then the volume of the cone, and after you can add the two volumes.

Cylinder:
V = π r^2 h
h = 12 inches
r = 4 inches
V = π(4^2)(12)
V = 192π

Cone:
V = 1/3 π r^2 h
h = 6 inches
r = 4 inches
V = 1/3 π (4^2)(6)
V = 32π

Now adding the two volumes, 192π + 32π = 224π cubic inches
3 0
3 years ago
Which of the following statements best describes the transverse axis of a
TEA [102]

Answer:

The transverse axis of a hyperbola equals the difference between the distances from any point on the hyperbola to each focus. Which is expressed in answer "C" in your list of possible answers.

Step-by-step explanation:

In fact, the definition of hyperbola is that of all point on the plane whose difference between their distance to each focus is a constant.

That constant can be determined in particular when one considers the distance to the actual vertex of the hyperbola (which is on the transverse axis) and whose distance to one of the focii is equal to the transverse axis plus the distance from the vertex to the focus, and from which needs to be subtracted the distance from the vertex to the focus, resulting then in exactly the transverse axis.

4 0
3 years ago
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