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larisa [96]
1 year ago
14

Use the net to find the surface area of the regular pyramid.

Mathematics
1 answer:
Svetradugi [14.3K]1 year ago
6 0

Answer:

7 or 7^{2}

Step-by-step explanation:

Each triangle has the surface area of 1.5, because 1 * 3 = 3 / 2 = 1.5. You divide by two because it is half a rectangle instead of a full one. You multiply by four which would get you 1.5 * 4 = 6. The square in the middle has the surface area of 1 because 1 * 1 = 1. So you would get 7.

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parallel when a=2

perpendicular when a=-1/2

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What Does 9/12 equal to?
sveticcg [70]
3/4 = or .75
Divide the numerator and denominator to reduce the fraction.
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Find the missing value in the equivalent ratio 18:27=
goblinko [34]

Answer:

18:27 can be reduced to 6:9 can be reduced again to 2:3.

6 0
2 years ago
Solve sin x - (3sin x-1) = 0
soldi70 [24.7K]

Answer:

\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}

Step-by-step explanation:

\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}

\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.

\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}

\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi

3 0
3 years ago
There are two numbers. The first number minus the second number is 15. One-third of the sum of the numbers is one quarter of the
disa [49]

Answer:

So the numbers are 12 and -3.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:

x - y = 15

Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:

(1/3)*(x+y) = x/4

Since we now have two equations and two variables we can solve for x and y. From the first equation we have:

y = x - 15

Using this expression for the value of y in the second equation:

(1/3)*(x + x - 15) = x/4

(1/3)*(2*x - 15) = x/4

2*x - 15 = 3*x/4

2*x - 3*x/4 = 15

(8*x - 3*x)/4 = 15

5*x/4 = 15

5*x = 60

x = 60/5 = 12

y = x - 15 = 12 - 15 = -3

So the numbers are 12 and -3.

4 0
2 years ago
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