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Lapatulllka [165]
2 years ago
6

The table of values for quadratic function g is shown below.

Mathematics
1 answer:
zavuch27 [327]2 years ago
6 0

Answer:

The table of values for a quadratic function g is shown below.x= -3, -2, -1, 0, 2, 3, 4, 6 g(x)= 48, 30, 16, 6, -2, 0, 6, 30 if 1 is a solution ...

1 answer

 ·  5 votes: try with 6 !!!!!!!!!!!!

Step-by-step explanation:

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Solve for V<br> 1 - 5V = V + 9 – 10V
denpristay [2]

Answer:

2

Step-by-step explanation:

1-5V=V+9-10V

1-5V-V-(-10V)=9

1-5V-V+10V=9

1-6V+10V=9

1+4V=9

4V=9-1

4V=8

V=8/4

V=2

7 0
2 years ago
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(2x+4)^2 - (x-5)^2 = 26x<br> Please solve (explained)
Zina [86]

Expand the squared binomials:

(2x+4)^2=4x^2+16x+16

(x-5)^2=x^2-10x+25

Then

(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x

\implies3x^2-9=0

\implies3x^2=9

\implies x^2=3

\implies x=\pm\sqrt3

5 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
Which of the following statements are true?
Kobotan [32]

Answer:I believe the answer is D

Step-by-step explanation:

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A car uses 5 2/3 gallons of gas for a 2 hour trip. how many gallons were used each hour
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It would use 2.83 gallons of gas for a 2 hour trip
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