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Andrew [12]
2 years ago
15

In the data set below, what are the lower quartile, the median, and the upper quartile?

Mathematics
1 answer:
Studentka2010 [4]2 years ago
3 0

The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

<h3>What is the Median?</h3>

The center value or middle value of a data set is the median.

<h3>What are the Upper and Lower Quartiles?</h3>

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

Learn more about the Median, Upper and Lower Quartiles on:

brainly.com/question/15572643

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I need help with letters (D) and (E). My model equation from letter (C) is: P = -55/4 t+ 340.
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Answer:

(a) The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope is m = -55/4

The slope means the rate of decreases of the owl population was 55/4

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(c) The model equation is P = -55/4 t + 340

(d) The owl population in 2022 will be 216

(e)  At year 2038 will be no more owl in the park

Step-by-step explanation:

* Lets explain how to solve the problem

- The owl population in 2013 was measured to be 340

- In 2017 the owl population was measured again to be 285

- The owl population is P and the time is t where t measure the numbers

 of years since 2013

(a) Let t represented by the x-coordinates of the order pairs and P

   represented by the y-coordinates of the order pairs

∵ t is measured since 2013

∴ At 2013 ⇒ t = 0

∵ The population P in 2013 was 340

∴ The first order pair is (0 , 340)

∵ The time from 2013 to 2013 = 2017 - 2013 = 4 years

∴ At 2017 ⇒ t = 4

∵ The population at 2017 is 285

∴ The second order pair is (4 , 285)

* The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope of any lines whose endpoints are (x1 , y1) and (x2 , y2)

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∵ (x1 , y1) is (0 , 340) and (x2 , y2) is (4 , 285)

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∴ m = \frac{285-340}{4-0}=\frac{-55}{4}

* The slope is m = -55/4

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* The slope means the rate of decreases of the owl population was

  55/4 per year (<em>P decreased by 55/4 each year</em>)

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∵ P = -55/4 t + 340

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- To find the year add 25 years to 2013

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