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Novay_Z [31]
2 years ago
7

Hi, I'm often really slow at learning math and my condition makes it harder, can someone help me?

Mathematics
1 answer:
NARA [144]2 years ago
7 0
The answer: 0, 4/5 and 5


Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero

Having said that, if:
2x = 0
X=0

If:
(5x^2-29x+20) = 0
X=4/6, x=5

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Given that ( x + 5 ) is a factor of the function f ( x ) = x^3 + x^2 − 17x + 15 , find the zeros, and write f ( x ) in factored
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The fully factored form of the function f(x) is : (x+5)(x-1)(x-3)

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Given function f(x)= x³+x²-17 x+15 is a third degree polynomial. Hence, it will have 3 zeros.


Also, <u><em>(x+5) </em></u>is the factor of given function.

⇒(x+5) divides the function f(x).

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hence, <em>x²-4 x+3 ⇔ (x -1)(x-3)</em>

From, equation (1),(2) the factors of<u><em> f(x) = x³+x²-17 x+15 are  (x -1)(x-3)(x-5)</em></u>

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