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MatroZZZ [7]
2 years ago
9

There are 13 buttons in a bag 9 buttons are white. 4 buttons are black Carol takes a button at random from the bag, and keeps it

She now takes another button from the bag. Work out the probability that Carol takes a button of each colour.​
Mathematics
2 answers:
inna [77]2 years ago
6 0
Answer is Case 1st
P(of white button) = 9/13
P(of black button) = 4/12
Case 2nd
P(of black button) = 4/13
P(of white button) = 9/12

Explanation: Given : A Question
To find : Probability
Solution : Case 1st
If carol takes the first button is white
P(of picking a white button) = 9/13
And
P(of picking a black button) = 4/12
Case 2nd
If carol takes the first button is black
So, P(of picking a black button) = 4/13
And P(of picking a white button) = 9/12

I hope this helps.
arlik [135]2 years ago
5 0

Step-by-step explanation:

Answer is case 1st:

P(of white button) = 9/13

P(of black button) = 4/12

Case 2nd

P(of black button) = 4/13

P(of white button) = 9/12

Explanation

Given: A Question

To find: Probability

Solution :Case 1st

If carol takes the first button is white

P(of picking a white button) = 9/13

And

P(of picking a black button) = 4/12

Case 2nd

If carol takes the first button is black

So, P(of picking a black button) = 4/13

And P( of picking a white button) = 9/12

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In AIJK, the measure of K=90°, the measure of I=74°, and JK = 6 feet. Find the length of IJ to the nearest tenth of a foot.
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Answer:

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Step-by-step explanation:

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The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
1 year ago
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