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Verdich [7]
3 years ago
5

How many and what type of solutions does 7x^2−4x+3 have? 1 rational solution 2 rational solutions 2 irrational solutions 2 nonre

al solutions
Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0

Answer:

2 non real solutions.

Step-by-step explanation:

We need to use discriminant,

for ax²+bx+c=0

The discriminat is b²-4ac

If the discriminant is,

→ less than 0, then 0 real solutions

→ equal to 0, then 1 real solutions

→ more than 0, then 2 real solutions

Given that,

7x²−4x+3=0

a=7, b=-4, and c=3

→ (-4)²-4(7)(3)

→ 16-84

→ -68

You can see this is less than 0, then non real solutions. [2 nonreal solutions]

Vikki [24]3 years ago
5 0

Answer:

Solution given:

7x²-4x+3=0

taking common 7

7(x²+4/7*x+3/7)=0

x²+2*x*2/7+(2/7)²-(2/7)²+3/7=0

(x+2/7)²=-17/49

x+2/7=\sqrt{\frac{17}{49}}

x=±√(17)/7-2/7

taking positive

x=√(17)/7-2/7

x=0.39

taking positive

x=-√(17)/7-2/7

x=-0.87

<u>2</u><u>:</u><u>u</u><u>n</u><u>r</u><u>e</u><u>a</u><u>l</u><u> </u><u>number</u>

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Answer:

\displaystyle d \approx 6.4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  1. Substitute in points [Distance Formula]:                                                   \displaystyle d = \sqrt{(-3+8)^2+(-2+6)^2}
  2. [√Radical] (Parenthesis) Add:                                                                        \displaystyle d = \sqrt{(5)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{25+16}
  4. [√Radical] Add:                                                                                              \displaystyle d = \sqrt{41}
  5. [√Radical] Evaluate:                                                                                        \displaystyle d = 6.40312
  6. Round:                                                                                                            \displaystyle d \approx 6.4
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