Answer:
86.16
Step-by-step explanation:
27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5
PEMDAS
Multiply and divide first
3/3 is 1 and 75/5 = 15
Replace these into the equation
27+1 +4-1+72.4-34.24+6-4+15
Then add and subtract from left to right
31 +72.4-34.24+6-4+15
69.16+6-4+15
86.16
Answer:
The correct answer is 12.8 J.
Step-by-step explanation:
To solve this problem, we must remember how to calculate the kinetic energy of an object.
The kinetic energy is represented by the formula K = 1/2 * m * v^2, where m represents the mass of the object and v represents the speed or velocity of the object. If we plug in the given values into the formula, we get:
K = 1/2 * m * v^2
K = (1/2) * (0.40) * (8.0)^2
Our first step is to square the velocity. After doing this step, we get the following:
K = (1/2) * (0.40) * (64)
Finally, we can perform the multiplication, to get:
K = 12.8
The unit for kinetic energy is joules, so the correct answer is 12.8 J.
Hope this helps!
Answer:
68 %
Step-by-step explanation:
Since we have our mean x = 250 and standard deviation σ = 20, we need to find how many standard deviations away the values 230 and 270 are.
Note x - σ = 250 - 20 = 230 and x + σ = 250 + 20 = 270
The values are one standard deviation away.
So, the values between 230 and 270 lie in the range x - σ to x + σ.
Since the batting averages are approximately normally distributed and for a normal distribution, 68 % of the values lie in the range x - σ to x + σ.
So, 68 % of Braves players fall between 230 and 270.
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:

So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.