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Usimov [2.4K]
3 years ago
9

What shapes can you obtain by taking a cross section of a cone?

Mathematics
1 answer:
SashulF [63]3 years ago
7 0
You can get a circle by cutting horizontally and a hyperbola by cutting vertically. You can also get an ellipse and a parabola by cutting at an angle depending on whether the cut comes out the other side or not. 

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What is the solution of 13 = t + 7 t​
atroni [7]

Answer:

t=1.625

Step-by-step explanation:

13=8t

divide both sides by 8

t=1.625

5 0
3 years ago
Help me please......................
OverLord2011 [107]
60 is 15
30 is 6
75 is 12
35 is 7
That’s the answer
3 0
1 year ago
Put these numbers from least to greatest. I'm too lazy to do it. it's for trigonometry.
blagie [28]

Answer:

15, 20, 25, 40, 50, 55, 65, 70, 75, 80, 85, 95

Hope this was all the numbers.

:)

8 0
2 years ago
Read 2 more answers
15 points. Please answer as soon as possible.
abruzzese [7]

Answer:

A. \frac{(a-b)^{2} +b^{2} }{a^{2}}

Step-by-step explanation:

So to get the area of a square, we need to find the length of one side.  

We know the length of the larger square is a, so the area of the larger cube is a^{2}

We can find the length of a side of the smaller square by using pythagoreans theorem to find the hypotenuse of the triangle formed in the bottom left corner.  The length of one side along the x axis is a - b, and the length of the other side, along the y-axis, is b.

We can plug it into pythagoreans theorem to get

(a-b)^{2} +b^{2} = C^{2} (C represents the length of one side of the smaller square, and the hypotenuse of the triangle)

C = \sqrt{ (a-b)^{2} +b^{2}}

The area of the smaller triangle is C squared to the area of the smaller triangle is

(a-b)^{2} +b^{2}

To get the ratio of the smaller square in comparison to the larger square we divide the area of the smaller square by the area of the larger square.

So the ratio should be

\frac{(a-b)^{2} +b^{2} }{a^{2}}

8 0
3 years ago
Divide z by 11. Then, add 8.
yulyashka [42]
This may be the answer,hope it helps

8 0
3 years ago
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