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2 years ago

Which of the following could be the side lengths of a triangle?

Mathematics

1 answer:

murzikaleks [220]2 years ago

4 0

Answer:

D. 12, 15, 25

Step-by-step explanation:

The triangle leg rule states that the smaller two lengths must add up to be greater than the largest length.

This means that the first two values must add up to be greater than the final value.

12 + 15 = 27

27 > 25

So, your answer is D

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Plz answer this now anyone

bearhunter [10]

answer is f hope u like it plz mark me as brainliest plzzzzzzzzzzzzz

5 0

2 years ago

P= 2(i+w) what is the solution for I?

Dafna11 [192]

First you had to switch sides of equation.

$2(i+w)=p$

Then you divide by two from both sides of equation form.

$\frac{2(i+w)}{2}= \frac{p}{2}$

Simplify.

$i+w=\frac{p}{2}$

Next, subtract by i from both sides of equation form.

$i+w-i=\frac{p}{2}-i$

Finally, simplify by equation.

$w=\frac{p}{2}-i$

Final answer: $\boxed{w=p/2-i}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

8 0

3 years ago

What is an equation of the line that passes through the point (2,−6) and is parallel to the line x-2y=8

lana [24]

Answer:

$y=\frac{1}{2}x-7$ , or x-2y=14

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through the point (2, -6) and is parallel to the line x-2y=8

First, we need to find the slope of x-2y=8, since parallel lines have the same slopes

We can convert the equation from standard form (ax+by=c) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept), in order to help us find the slope of the line

Start by subtracting x from both sides

-2y=-x+8

Divide both sides by -2

y= $\frac{1}{2}x$ -4

The slope of the line x-2y=8 is 1/2

It's also the slope of the line parallel to it.

Since we know the slope of the line, we can plug it into the equation for slope intercept form:

$y=\frac{1}{2}x+b$

Now we need to find b.

As the equation of the line passes through (2, -6), we can use it to help solve for b

Substitute -6 as y and 2 as x:

$-6=\frac{1}{2}(2)+b$

Multiply

-6=1+b

Subtract 1 from both sides

-7=b

Substitute -7 as b into the equation:

$y=\frac{1}{2}x-7$

The equation can be left as that, or you can convert it into standard form if you wish.

In that case, you will need to move 1/2x to the other side:

$-\frac{1}{2}x+y=-7$

A rule about the coefficients a, b, and c in standard form is that a (coefficient in front of x) CANNOT be negative, and every coefficient must be an integer (a whole number, not a fraction or decimal).

So multiply both sides by -2 in order to clear the fraction, as well as change the sign of a

x-2y=14

Hope this helps!

8 0

2 years ago

If (8,-2) is on the graph of F(x), which point must be on the graph of the inverse funtion F^-1(x)?

FromTheMoon [43]

If the point ( 8,-2) is on F(X) that a point ( -2,8) must be on the graph of the inverse fraction F^-1 (x) because the invers of a function is found by inversing the coordinate x and y.

5 0

3 years ago

Read 2 more answers

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

2 years ago