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Jlenok [28]
2 years ago
6

Use the function f(x) = x2 − 2x 8 and the graph of g(x) to determine the difference between the maximum value of g(x) and the mi

nimum value of f(x). a parabola that opens down and passes through 0 comma 3, 3 comma 12, and 5 comma 8 2 5 7 12
Mathematics
1 answer:
slamgirl [31]2 years ago
6 0

The difference between the maximum value of g(x) and the minimum value of f(x) is 5.

Given function is:

f(x)=x^{2} -2x+8......(1)

<h3>What is the general form of a quadratic equation?</h3>

The general form of a quadratic equation is ax^{2} +bx+c=0 with a\neq 0.

As we know the minimum value of a quadratic function is \frac{4ac-b^{2} }{4a} when a>0

For f(x) a>0 so minimum value of f(x) = \frac{4*1*8-(-2)^2}{4*1}=7

From the graph, the maximum value of g(x) =12

So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5

Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.

To get more about quadratic functions visit:

brainly.com/question/1214333

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7 0
3 years ago
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
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Zarrin [17]

Answer:

I believe it is 1728 cubic centimeters, however I might be wrong

Hope it helps : )

Step-by-step explanation:

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const2013 [10]

Answer:

-11 \frac{1}{4}

Step-by-step explanation:

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