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2 years ago

Hey just doing this so you can get some points

Mathematics

1 answer:

lara31 [8.8K]2 years ago

4 0

Answer:

thank you very much xoxo

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find all possible value of the given variable

mamaluj [8]

$1.\\ \\ h^2+5h=0 \\ \\h(x+5)=0\\ \\x=0 \ \ \ or \ \ \ x+5 =0\ \ |-5\\ \\x+5-5=0-5\\ \\x=0 \ \ \ or \ \ \ x=-5$

$2.\\ \\ z^2-z=0\\ \\z(x-1)=0\\ \\z=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\\ \\z-1+1 =0 +1 \\ \\x=0 \ \ \ or \ \ \ z=1$

$3.\\ \\m^2+13m+40=0 \\ \\a=1 ,\ b=13, \ c=40 \\ \\\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \\ \\and \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution$

$4.\\ \\z^2-3z=0 \\ \\ (z-3)=0\\ \\z=0 \ \ \ or \ \ \ z-3 =0\ \ |+3\\ \\ z-3+3=0+3\\ \\z=0 \ \ \ or \ \ \ z=3$

$5.\\ \\q^2+7q=0 \\ \\q(q+7)=0\\ \\q=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\\ \\q+7-7=0-7\\ \\q=0 \ \ \ or \ \ \ q=-7$

$6.\\ \\k^2+2k=0\\ \\k(k+2)=0\\ \\k=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\\ \\k+2-2=0-2\\ \\k=0 \ \ \ or \ \ \ k=-2$

$7. \\ \\ x^2-3x-70=0 \\ \\a=1,\ b=-3, \ c=-70 \\ \\\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{3-\sqrt{289}}{2 }=\frac{ 3-17}{2}=\frac{-14}{2}=-7$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{3+\sqrt{289}}{2 }=\frac{ 3+17}{2}=\frac{20}{2}=10\\ \\(x+7)(x-10)=0$

$8.\\ \\q^2+7q-60=0 \\ \\a=1,\ b=7, \ q=-60 \\ \\\Delta =b^2-4ac = 7^2-4\cdot 1\cdot (-60)=49+240=289 \\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-7-\sqrt{289}}{2 }=\frac{ -7-17}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-7+\sqrt{289}}{2 }=\frac{ -7+17}{2}=\frac{ 10}{2}= 5\\ \\(x+12)(x-5)=0$

$9.\\ \\z^2+9z-36=0 \\ \\a=1,\ b=9, \ q=-36 \\ \\\Delta =b^2-4ac = 9^2-4\cdot 1\cdot (-36)= 81+144=225\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{225}}{2 }=\frac{ -9-15}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{225}}{2 }=\frac{ -9+15}{2}=\frac{6}{2}=3\\ \\(x+11)(x-3)=0$

$10.\\ \\d^2-13d+22=0 \\ \\a=1,\ b=-13, \ q=22 \\ \\\Delta =b^2-4ac = (-13)^2-4\cdot 1\cdot 22= 169-88=81\\ \\ d_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{13-\sqrt{81}}{2 }=\frac{ 13-9}{2}=\frac{4}{2}=2$

$d_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{13+\sqrt{81}}{2 }=\frac{ 13+9}{2}=\frac{22}{2}=11\\ \\(d-2)(d-11)=0$

7 0

3 years ago

What is the measure of angle 1?<br> 36°<br> 86°<br> 89°<br> 94°

den301095 [7]

Answer:

94°

Step-by-step explanation:

Remember that the sum of the interior angles of a triangle is 180°. To do it the easier (but longer) way, simply do the following. Add all the interior angles up, and subtract it from 180 to get the angle you do not know, and then solve for angle 1:

180 = (29 + 65 + m∠2)

= 180 - 94 = m∠2

= m∠2 = 86°

Next, note that ∠1 & ∠2 are directly next to each other. When this occurs, solve for their supplementary angle. We know that m∠2 = 86°. Supplementary Angle = 180°:

180 - 86 = 94°

m∠1 = 94°.

The simpler way to solve this, is to first note that it is a triangle. To solve for the outlier angle, simply add the two opposite angles together to get your answer:

m∠1 = 29 + 65

m∠1 = 94°.

3 0

2 years ago

Read 2 more answers

What kind of sequence has a common difference?

Jet001 [13]

Answer:

arithemetic sequence i guess

3 0

3 years ago

Read 2 more answers

Kim orders catering from Midtown Dinerfor $35. She spends $5 on a large order of potato salad and the rest on turkey sandwich. E

aivan3 [116]

Answer:

Kim had bought 12 sandwiches.

Step-by-step explanation:

Given:

Amount spend at Midtown Dine = $35

Amount spend on large order of potato salad = $5

Cost of each sandwich = $2.5

We need to find the number of sandwich did Kim bought.

Solution:

Let the number of sandwich Kim bought be 'x'.

Now we know that;

Amount spend at Midtown Dine is equal to sum of Amount spend on large order of potato salad and number of sandwich Kim bought multiplied by Cost of each sandwich.

framing in equation form we get;

$5+2.5x=35$