Hey just doing this so you can get some points

Name a segment that is perpendicular to segment AB.<br> G<br> E<br> A<br> D<br> H<br> F<br> B<br> С

zlopas [31]

Answer:

BC

Step-by-step explanation:

7 0

3 years ago

Artie's dad's house is 21 ft tall. If Artie's dad is at the top of the house installing shingles, and his son Artie is on the gr

konstantin123 [22]

Answer:

B. 60.26°

Step-by-step explanation:

Given:

Consider the diagram representing the above scenario.

The top of the house where dad is standing is at A. The point where his son is standing is B. The bottom of the house is at C. AC is the height of house, BC is the distance between the house and son.

Height of the house (AC) = 21 ft

Distance between the house and son (BC) = 12 ft

Let the angle of depression for the dad be 'x'.

From the figure, it is clear that,

Angle of depression of the dad will be same as angle of elevation of Artie.

For triangle ABC,

$\tan x=\frac{AC}{BC}\\\\\tan x=\frac{21\ ft}{12\ ft}\\\\\tan x=1.75\\\\x=\tan^{-1}(1.75)\\\\x=60.26$

Therefore, the angle of depression from the top of the house to the spot where Artie is standing is 60.26°.

Therefore, the correct option is option (B).

6 0

3 years ago

Find the missing endpoint if one endpoint is at (5.-7) and the midpoint is at (15.1).

ioda

Answer:

(25, 9)

Step-by-step explanation:

<h3>Given </h3>

Point (5, -7) and midpoint (15, 1)

Missing endpoint

<h3>Solution</h3>

<u>Midpoint formula:</u>

x = (x1 + x2)/2,
y = (y1 + y2)/2

<u>Substituting values:</u>

15 = (5 + x2)/2 ⇒ 5 + x2 = 30 ⇒ x2 = 30 -5 ⇒ x2 = 25
1 = (-7 + y2)/2 ⇒ -7 + y2 = 2 ⇒ y2 = 2 - (-7) ⇒ y2 = 9

<u>Missing endpoint is:</u>

(25, 9)

7 0

3 years ago

Find the area of the figure shown.

astraxan [27]

Answer:220

Step-by-step explanation:

LET X BE THE LENGTH OF RECTANGLE AND FOR UPPER PORTION OF DIA GRAM BASE OF RIGHT ANGLE TRIANGLE SO X=20

LET Y BE WIDTH OF RECTANGLE SO Y=8

LET P BE THE PERPENDICULAR OF THE RIGHT TRIANGLE SO P=6

THEN

AREA OF RECTANGLE=LENGTH*WIDTH

SO AREA OF RECTANGLE BECOMES=(20)(8)=160

AND AREA OF RIGHT ANGLE TRIANGLE BECOMES=1/2(BASE*(PERPENDICULAR)

SO =1/2(20)(6)=60

SO THE TOTAL AREA OF THE DIAGRAM=AREA OF RIGHT ANGLE TRIANGLE+AREA OF RECTANGLE=160+60=220

6 0

2 years ago

Solve this problem, which steps would you take? Include any theorems, definitions, or reasons that explain the steps. Make sure

posledela

Answer:

∠A=123°.

Step-by-step explanation:

From the given figure it is clear the CD and CE are two tangent lines on circle with center A.

Radius is perpendicular to the tangent at the point of tangency.

$\angle ADC=90^{\circ}$

$\angle AEC=90^{\circ}$

Smaller arc DE = (5x-2)°

It means central angle DAE is (5x-2)°.

$\angle DAE=(5x-2)^{\circ}$

Now, ADCE is a quadrilateral and sum of all angles of a quadrilateral is 360 degrees.

$\angle ADC+\angle DCE+\angle AEC+\angle DAE=360^{\circ}$

$90^{\circ}+(2x+7)^{\circ}+90^{\circ}+(5x-2)^{\circ}=360^{\circ}$

$(7x+5)^{\circ}+180^{\circ}=360^{\circ}$

$(7x+5)^{\circ}=360^{\circ}-180^{\circ}$

$(7x+5)^{\circ}=180^{\circ}$

$7x+5=180$

$7x=175$

$x=25$

The value of x is 25.

$\angle A=5x-2=5(25)-2=125-2=123^{\circ}$

Therefore, the measure of ∠A is 123°.

6 0

2 years ago