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2 years ago

30 POINTS!! Find the equation of the axis of symmetry of the parabola. Each box in the grid represents 1 unit.

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

7 0

The axis of symmetry is at X = 2

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We are throwing darts on a disk-shaped board of radius 5. We assume that the proposition of the dart is a uniformly chosen point

Vlad1618 [11]

Answer:

the probability that we hit the bullseye at least 100 times is 0.0113

Step-by-step explanation:

Given the data in the question;

Binomial distribution

We find the probability of hitting the dart on the disk

⇒ Area of small disk / Area of bigger disk

⇒ πR₁² / πR₂²

given that; disk-shaped board of radius R² = 5, disk-shaped bullseye with radius R₁ = 1

so we substitute

⇒ π(1)² / π(5)² = π/π25 = 1/25 = 0.04

Since we have to hit the disk 2000 times, we represent the number of times the smaller disk ( BULLSEYE ) will be hit by X.

X ~ Bin( 2000, 0.04 )

n = 2000

p = 0.04

np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥ $\frac{100-80}{\sqrt{76.8} }$ )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

3 0

3 years ago

Sketch the angle in standard position and draw an arrow representing the correct amount of rotation. Find the measure of two oth

ser-zykov [4K]

Answer:

The coterminal angles are : 270° , -450°

sketched angle is in third quadrant

Step-by-step explanation:

The sketch of the angle in standard position is attached below

The coterminal angles :

- 90 + 360 = 270°

-90 - 360 = -450°

Quadrant of the angle( -90° ) = Third quadrant

6 0

3 years ago

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dis

Ronch [10]

<h2>Complete Question: </h2>

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.

1. $\frac{2}{3} $ and $ \frac{1}{3}$

2. $\frac{3}{4} $ and $ \frac{1}4}$

3. $\frac{4}{7} $ and $ \frac{7}{8}$

4. $\frac{2}{5} $ and $ \frac{5}{11}$

5. $\frac{7}{13} $ and $ \frac{7}{9}$

<h2>The answers:</h2>

1. $\frac{2}{3} $ and $ \frac{1}{3}$ - Similar (S)

2. $\frac{3}{4} $ and $ \frac{1}4}$ - Similar (S)

3. $\frac{4}{7} $ and $ \frac{7}{8}$ - Dissimilar (D)

4. $\frac{2}{5} $ and $ \frac{5}{11}$ - Dissimilar (D)

5. $\frac{7}{13} $ and $ \frac{7}{9}$ - Dissimilar (D)

Note:

Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.

Thus:

1. $\frac{2}{3} $ and $ \frac{1}{3}$ - They have equal denominator. Both fractions are similar (S).

2. $\frac{3}{4} $ and $ \frac{1}4}$ - They have equal denominator. Both fractions are similar (S).

3. $\frac{4}{7} $ and $ \frac{7}{8}$ - They have equal denominator. Both fractions are dissimilar (D).

4. $\frac{2}{5} $ and $ \frac{5}{11}$ - They have equal denominator. Both fractions are dissimilar (D).

5. $\frac{7}{13} $ and $ \frac{7}{9}$ - They have equal denominator. Both fractions are dissimilar (D).

Therefore, the fractions in 1 and 2 are similar (S) while those in 3, 4, and 5 are dissimilar (D).

Learn more here:

brainly.com/question/22099172

7 0

3 years ago

Plz help me!!!!!!!!!!!!!!!!!!!!

miss Akunina [59]

There are 5 dimes and 13 nickels

5 0

3 years ago

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0

2 years ago