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ipn [44]
3 years ago
7

The package shown is shaped like a right rectangular prism. Every side of the package will be covered with gift wrap, except the

bottom side. How many square inches of gift wrap will be needed? please help!!
L = 16
W = 10
H = 12
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
<span> three-dimensional figure has length, width, and height. A face is a flat </span>side<span>. A vertex is .... Describe the faces edges and vertices of </span>each<span> three dimensional ... Vera's closet is </span>in the shape of<span> a </span>rectangular prism<span>. ... You </span>can<span> draw different views of three-dimensional figures. .... How </span>many square<span> millimeters of</span>wrapping paper<span>.</span>he amount of wrapping paper needed<span> to </span>cover<span> the figure represents its surface area. To find the surface area, you calculate the area of </span>each<span> face or </span>side<span> ... where SA = surface area, </span>l<span> = length, </span>w<span> = width, and </span>h<span> = height. ... the surface area of this </span>prism<span> is 158 </span>square inches<span>.  

</span>
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Please Help. Due Soon!
djyliett [7]

Answer:

yes

Step-by-step explanation:

They are correct because the reciprocal ( flipped or opposite) of -2/5 is 5/-2

5 0
3 years ago
HELP 30 POINTS please in a hurry
eimsori [14]

To be a function every input value (x) can only have one output value (y)

On the graph there are 2 out put values for x = 2 so it is not a function.

The answer would be C.

8 0
3 years ago
Thi sis the question
jek_recluse [69]

\text{Given that,}\\\\x^2 + \dfrac1{x^2} = 38\\\\\\(i)\\\\\left(x-\dfrac 1x \right)^2 = x^2 + \dfrac 1{x^2} - 2 \cdot x \cdot \dfrac 1x\\\\\\\implies \left(x-\dfrac 1x \right)^2 = 38 -2 = 36\\\\\implies x - \dfrac 1x = \pm\sqrt{36} = \pm 6 \\\\\\(ii)\\\\x^2 + \dfrac 1{x^2} = 38\\\\\\\implies \left(x^2 + \dfrac 1{x^2} \right)^2 = 38^2\\\\\\\implies x^4 + \dfrac 1{x^4} + 2\cdot x^2 \cdot \dfrac 1{x^2} = 1444\\\\\\\implies x^4 + \dfrac 1{x^4} + 2 = 1444\\\\\\

\implies x^4 +\dfrac 1{x^4} = 1444-2 = 1442

7 0
2 years ago
Find the value of y please ASAP
nekit [7.7K]

x/3 = 12/x

x^2 = 36

x = 6

9/y = y /x

9/y = y / 12

y^2 = 9 * 12

y = 9 * 4 * 3

y = 6√3

Answer

y = 6√3

5 0
3 years ago
Read 2 more answers
A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0
3 years ago
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