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4 years ago

Please help asap 25 pts

Mathematics

2 answers:

miv72 [106K]4 years ago

7 0

f(-2)=3(-2) +4

f(-2)=-6+4

f(-2)=-2

Kryger [21]4 years ago

5 0

For this case we have a function of the form:

$y = f (x)$

Where $f (x) = 3x + 4$

If we have the value of $x = -2$ , substituting we have:

$f (-2) = 3 (-2) +4$

We solve the multiplication taking into account that + * - = - and $3 * 2 = 6$

$f (-2) = - 6 + 4$

It is known that different signs are subtracted and the sign of the major is placed.

$f (-2) = - 2$

Thus, $f (x) = 3x + 4$ evaluated at $x = -2$ is: $f (-2) = - 2$

Answer:

$f (-2) = - 2$

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Step-by-step explanation:

v = 42
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3 years ago

Write an equation of a function that is not linear

arlik [135]

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3 years ago

four 3 megawatt wind turbines can supply enough electricity to power 3000 homes. How many turbines would be required to power 55

fiasKO [112]

Answer:

The number of turbines is 74

Step-by-step explanation:

* Lets explain how to solve the problem

- Four 3 megawatt wind turbines can supply enough electricity

to power 3000 homes

∴ The number of turbines is 4

∵ Each turbine give 3 megawatt

∴ The four turbines give ⇒ 4 × 3 = 12 megawatt

- This quantity give enough electricity to power 3000 homes

∴ The number of homes for the 12 megawatt is 3000

- We need to find how many turbines can cover enough electricity

to power 55,000 homes, so we must to know the quantity of

electricity that be enough to power 55,000 homes

* Lets use the cross multiplication to solve the problem

∵ megawatt : number of homes

12 : 3,000

? : 55,000

- By using cross multiplication

∴ $?=\frac{(55,000)(12)}{3,000}=\frac{660,000}{3000}=220$

∴ The enough electricity to power 3000 homes = 220 megawatt

∵ Each turbine gives 3 megawatt

- Find the number of turbines divides the total megawatt by the the

megawatt of one turbine

∴ The number of turbines = 220 ÷ 3 = 73.3

- If we take 73 only the electricity will not be enough to cover all

homes, so we must to take 74 turbines

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4 years ago

A math class's mean test score is 88.4. The standard deviation is 4.0. If Kimmie scored 85.9, what is her z-score

kvv77 [185]

The z-score of Kimmie is -0.625

<h3>Calculating z-score</h3>

The formula for calculating the z-score is expressed as;

z = x-η/s

where

η is the mean

s is the standard deviation

x is the Kimmie score

Substitute the given parameter

z = 85.9-88.4/4.0

z = -2.5/4.0

z = -0.625

Hence the z-score of Kimmie is -0.625

Learn more on z-score here: brainly.com/question/25638875

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2 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago