Aquifers store water in ground.
Answer:
b. + 1.01 V
Explanation:
Sn(s) ⇒ Sn2+ + 2e⁻ Eox = 0.14 V
Ag₊ + e⁻⇒ Ered = 0.80 V
_______________________________
Sn(s) + Ag⁺(aq) ⇒ Sn2⁺(aq) + Ag(s) Eºcell = 0.14 V + 0.80 V = 0.94 V
This problem is solved by using the Nernst equation:
Ecell = Eºcell - (0.0592 / n) log Q
since we are not at standard condition given that the concentrations are not at 1 M. So we will calculate Q first
Q = ( Sn²⁺ ) / ( Ag⁺) = 0.022/2.7 = 0.0081
Ecell = 0.94 V -(0.0592/2) x log (0.0081) = 1.00 V
I think it looks good but some grammars are wrong i suggest trying to put it on grammarly and just check it out its just my suggestion and not doing this for points so you can delete this if it doesnt help
By using the formula, mass = density x volume, we
calculate mass in grams
20.0 mL CH₃COOH x (1.05 g / mL) = 21.0
g CH₃COOH
To find the moles, molar mass of CH₃COOH = 60.05g/mol<span>
21.0 g </span>CH₃COOH x (1 mole CH₃COOH / 60.05 g CH₃COOH)
= 0.350 moles CH₃COOH
To find molarity,<span>
[</span>CH₃COOH] = moles CH₃COOH / L of solution = 0.350 /
1.40 = 0.250 M CH₃COOH<span>
When </span>CH₃COOH is dissolved in water, it produces
small and equal amounts of H₃O⁺+ and C₂H₃O₂⁻.
<span>
Molarity , </span>CH₃COOH<span> + H</span>₂O <==> H₃O⁺ + C₂H₃O₂⁻
<span>
<span>Initial 0.250 0 0 </span>
Change -x x x
Equilibrium 0.250-x x x
K</span>ₐ = [H₃O⁺][C₂H₃O₂⁻] / [HC₂H₃O₂] = (x)(x) /
(0.250-x) = 1.8 x 10⁻⁵
<span>Since K</span>ₐ is relatively small, we can neglect the -x
term after 0.250 to simplify
<span>x</span>² / 0.250 = 1.8 x 10⁻⁵
x² = 4.5 x 10⁻⁶
<span>
x = 2.1 x 10</span>⁻³<span> = [H</span>₃O⁺]
pH = -log [H₃O⁺] = -log (2.1 x 10⁻³) = 2.68
Explanation:
A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.
This is because it tells in what state the reactants were present and in what state the products are then formed.
For example,
Now here, (aq) means aqueous, (l) means liquid and (g) means gas.
So, these states denoted are necessary as it tells that in aqueous state dissociates to give in liquid state and in gaseous state.