Question

From Young's experiment, how does the frequency of light affect the number of lines observed?

Answer 1

Answer:

A: Higher frequencies equal more lines

Explanation:

I took the test and that's the answer. (See screen shot below)

Answer 2

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

$dsin\theta=n\lambda$.........(1)

n is order or number of lines observed

d is distance between slits

$\theta$ is the angle between the path and the line from screen to the slits.

We also know that, $c=\nu \lambda$

or

$\lambda=\dfrac{c}{\nu}$

where,

c is the speed of light

$\nu$ is frequency

$\lambda$ is wavelength

So, equation (1) turns into

$dsin\theta=n\dfrac{c}{\nu}$

$\nu=\dfrac{n\ c}{d\ sin\theta}$

So,

$\nu\propto n$

or

Higher frequencies have larger spaces between line.

So, correct option is (C).