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3 years ago

Why are some elements more reactive than others?

Chemistry

2 answers:

nlexa [21]3 years ago

8 0

Because of extra electrons

steposvetlana [31]3 years ago

4 0

All other atoms have less stable electron numbers, so they react with each other and share electrons to be more stable. The most reactive elements tend to be short one or two electron or have one or two extra electrons.

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Which elements are represented by the symbols S and Na?

Degger [83]

Sulfur and sodium are those two elements

4 0

3 years ago

In atomic absorption spectrophophometry, the term "nebulization" implies: (a) The breaking down of fine mist of liquid droplets

Gwar [14]

Answer:

Explanation:

Nebulization is the process by which a mist of a substance is introduced into a flame so that the free atoms are formed. The free atoms are now introduced into the light path for Atomic Absorption spectrophotometry.

8 0

3 years ago

Write the electron configuration of the element that has Z = 3 *

Natasha2012 [34]

Answer:

1s²2s^1

Explanation:

Lithium Z = 3

8 0

3 years ago

A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

3 years ago

Calculate the oxidation number for carbon in CH4

Maksim231197 [3]

Answer:

Explanation:

Oxidation number of neutral compound is 0

Oxidation number of hydrogen in methane is -1

C + (-1×4) = 0

C - 4 = 0

C = 4

8 0

2 years ago