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TEA [102]
3 years ago
12

Which figures are polygons?

Mathematics
2 answers:
Tema [17]3 years ago
7 0
The answer is A, B, and D
MA_775_DIABLO [31]3 years ago
4 0
Im pretty sure the answer would be A, B & D
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2 Points
Inga [223]

Answer:

D

Step-by-step explanation:

Given

9 - 7x = (4x - 3)² + 5 ← expand the squared factor

9 - 7x = 16x² - 24x + 9 + 5, that is

9 - 7x = 16x² - 24x + 14 ( subtract 9 - 7x from both sides )

0 = 16x² - 17x + 5, that is

16x² - 17x + 5 = 0 ← in standard form → D

4 0
3 years ago
What is the perimeter of the rectangle? one side is 6in. and the A=30 sq in.
monitta
The perimeter of a rectangle can be found by dividing the area by one side.
30/6=5
Then, add the sides up and you get the perimeter.
5+5+6+6=22

The answer is 22 inches.
3 0
3 years ago
Read 2 more answers
Can someone help me with this
Solnce55 [7]
Aye man , who wants to give me points
4 0
2 years ago
One<br> Find the product:<br> (n - 5)(n-1)
Elina [12.6K]
The answer is n^2-6n+5

4 0
3 years ago
Read 2 more answers
a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.
ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: \mathbf{Length = a -5} and \mathbf{Width = a^2 + 5a + 25}

The area is given as:

\mathbf{Area = a^3 - 125}

Express 125 as 5^3

\mathbf{Area = a^3 - 5^3}

Apply difference of cubes

\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}

\mathbf{Area = (a - 5)(a^2 + 5a + 25)}

The area of a rectangle is:

\mathbf{Area = Length \times Width}

So, by comparison:

\mathbf{Length = a -5}

\mathbf{Width = a^2 + 5a + 25}

Read more about areas at:

brainly.com/question/3518080

6 0
2 years ago
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