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3 years ago

-15X - 40 = 23 - 8 This is the problem and I am totally lost

2 answers:

Elena-2011 [213]3 years ago

3 0

-15x-40=15
then add 40 to both sides to get the constants on 1 side and variables on the other
-15x=25
now you just divide by -15
x = -1.67 or x = -1/3

romanna [79]3 years ago

3 0

Subtract 8 from both sides

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A graphing calculator is recommended. A crystal growth furnace is used in research to determine how best to manufacture crystals

Sophie [7]

Answer:

a) $w_1 = \frac{-2.156 -\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=-54.896$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=33.336$

And since the power can't be negative then the solution would be w = 33.34 watts.

b) $202= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-182=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-182)}}{2*0.1}=33.222$

$204= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-184=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-184)}}{2*0.1}=33.449$

So then the range of voltage would be between 33.22 W and 33.45 W.

c)For this case $\epsilon = \pm 1$ since that's the tolerance 1C

d) $\delta_1 =|33.222-33.336|=0.116$

$\delta_2 =|33.449-33.336|=0.113$

So then we select the smalles value on this case $\delta =0.113$

e) For this case if we assume a tolerance of $\epsilon=\pm 1C$ for the temperature and a tolerance for the power input $\delta =0.113$ we see that:

$lim_{x \to a} f(x) =L$

Where a = 33.34 W, f(x) represent the temperature, x represent the input power and L = 203C

Step-by-step explanation:

For this case we have the following function

$T(w)= 0.1 w^2 +2.156 w +20$

Where T represent the temperature in Celsius and w the power input in watts.

Part a

For this case we need to find the value of w that makes the temperature 203C, so we can set the following equation:

$203= 0.1w^2 +2.156 w +20$

And we can rewrite the expression like this:

$0.1w^2 +2.156 w-183=$

And we can solve this using the quadratic formula given by:

$w =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where a =0.1, b =2.156 and c=-183. If we replace we got:

$w_1 = \frac{-2.156 -\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=-54.896$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=33.336$

And since the power can't be negative then the solution would be w = 33.34 watts.

Part b

For this case we can find the values of w for the temperatures 203-1= 202C and 203+1 = 204 C. And we got this:

$202= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-182=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-182)}}{2*0.1}=33.222$

$204= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-184=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-184)}}{2*0.1}=33.449$

So then the range of voltage would be between 33.22 W and 33.45 W.

Part c

For this case $\epsilon = \pm 1$ since that's the tolerance 1C

Part d

For this case we can do this:

$\delta_1 =|33.222-33.336|=0.116$

$\delta_2 =|33.449-33.336|=0.113$

So then we select the smallest value on this case $\delta =0.113$

Part e

For this case if we assume a tolerance of $\epsilon=\pm 1C$ for the temperature and a tolerance for the power input $\delta =0.113$ we see that:

$lim_{x \to a} f(x) =L$

Where a = 33.34 W, f(x) represent the temperature, x represent the input power and L = 203C

8 0

4 years ago

In the function f(x) = 4(x2 âˆ’ 6x ) 20, what number belongs in the blank to complete the square?

vitfil [10]

The number to be added to the blank should be 9.

According to the statement

we have to find the number which is missing from the given expression.

So, For this purpose, We know that the

Expression in math is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given function is f(x) = 4(x² − 6x + ____) + 20. To complete the expression, complete the square of the one inside the parentheses. This is done by dividing the coefficient of x with 2 and then raising it to two.

-6/2 = -3

(-3)² = 9

Therefore, the number to be added to the blank should be 9.

Learn more about Expression here

brainly.com/question/723406

Disclaimer: This question was incomplete. Please find the full content below.

Question:

In the function f(x) = 4(x^2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

#SPJ4

7 0

2 years ago

Find the volume of the triangular prism

gulaghasi [49]

Answer:

V = 5280 in^3

Step-by-step explanation:

The volume is found by

V = Bh where B is the area of the base and h is the height

first we need to find the area of the base

The base is the triangle

We need to find the base dimension for the triangle

34^2 = 16^2 + b^2

34^2 -16^2 = b^2

900 = b^2

30 =b

B = 1/2 bh

= 1/2 (30) *16

B =240

V = Bh

V = 240 * 22

V = 5280 in^3

3 0

3 years ago

Is 10 the solution of the equation 4x - 8 = 31?

Tom [10]

4x-8 = 31

4x = 31 + 8

4x = 39

x = 9.75

6 0

3 years ago

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What expression has a term with a base of 8 z^8 8^4 3xy+8 8m

Elodia [21]

8m is the correct answer

4 0

3 years ago