An atom is electrically neutral because

Is it OK for people to post fake vacation pics and other fake info on social media? Why or why not? Use facts and details from t

asambeis [7]

Answer:

No, It is not okay to pretend on social media.

Explanation:

No, it is not okay for people to post fake vacation pics and other fake info on social media. This is very wrong, as -

This 'all time look good, feel good, have a happening life' approach of social media - implies showing only the positive side & not negative side of people's life. However, in real life is not a bed of roses.
Faking things out implies that pretending to be cool has become more important than sharing deep meaningful relationships, & highlights superficial desire of false popularity.
It is also harmful to people being communicated this fake image, as they might indulge into any social involvement, on the basis of unreal image of the concerned person.

3 0

3 years ago

Read 2 more answers

Aqueous aluminum bromide and solid zinc are produced by the reaction of solid aluminum and aqueous zinc bromide . write a balanc

Rashid [163]

3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s) The unbalanced equation is: ZnBr2 (aq) + Al (s) ==> AlBr3 (aq) +Zn (s) First, count the atoms of each element on each side of the equation: Zn 1,1 Br 2,3 Al 1,1 The zinc and aluminum, but the bromine doesn't match with 2 and 3. So look for the least common multiple of 2 and 3 which is 6 and adjust the quantities on both sides to have 6 bromine atoms on both sides. Do this by having 3 zinc bromide on the left and 2 aluminum bromide on the right, getting: 3 ZnBr2 (aq) + Al (s) ==> 2 AlBr3 (aq) +Zn (s) Now check the atom counts again for both sides: Zn 3,1 Br 6,6 Al 1,2 Now bromine matches, but zinc and aluminum doesn't. But it's easy enough to add an extra aluminum to the left and 2 more zinc to the right. Giving: 3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s) Now check the atom counts again: Zn 3,3 Br 6,6 Al 2,2 And they match. So the balanced equation is: 3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s)

8 0

3 years ago

Think about the typical weather conditions where you live. What is the name of the average yearly weather patterns in any one ar

Ludmilka [50]

CLIMATE

give me brainliest please

5 0

3 years ago

A particular uranium alloy has a density of 18.75 g/cm3. Please answer the following questions below, providing the explanation

zhannawk [14.2K]

Answer:

a) Critical mass of 49 kg of Uranium: 2600 cm³

b) Critical mass of 16 kg Uranium: 850 cm³

Comparison:

Baseball: 221 cm³

Basketball: 7,238 cm³

Baseball < Critical mass of 16 kg of uranium < critical mass of 49 kg of uranium < basketball.

Explanation:

To find the volumes of the two samples of uranium alloy, you must use the formula of density:

$Density=\dfrac{mass}{volume}\\\\\\Volume=\dfrac{mass}{density}$

a) Critical mass of 49 kg

First, notice that 18.75g/cm³ is the same that 18.75 kg/dm³ (to convert from grams to kg you must divide by 1,000, and to convert from cm³ to dm³ you must divide by 1,000; thus, dividing both numerator an denominator by the same number leaves the fraction unchanged).

Now you can compute:

$Volume=\dfrac{49kg}{18.75kg/dm^3}=2.6dm^3$