Question

What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4

Answer 1

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. The concentration of the solution is calculated as follows:

 

Molarity = 17 g (1 mol / 159.61 g) / 974 mL (1 L / 1000 mL)

Molarity = 0.109 M

Answer 2

Answer : The correct option is, (A) 0.109 M $CuSO_4$

Solution : Given,

Mass of $CuSO_4$ = 17 g

volume of solution = 974 ml

Molar mass of $CuSO_4$ = 159.609 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{w\times 1000}{M\times V_s}$

where,

w = mass of $CuSO_4$ (solute)

M = molar mass of $CuSO_4$

$V_s$ = volume of solution in liter

Now put all the given values in the above formula, we get the molarity of solution.

$Molarity=\frac{(17g)\times 1000}{(159.609g/mole)\times (974ml)}=0.109mole/L=0.109M$

Therefore, the molarity of the solution is, 0.109 M