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svlad2 [7]
3 years ago
6

What is the value for (delta)G at 1000 K if (delta)H = -220 kJ/mol and (delta)S = -0.05 kJ/(molK)?

Chemistry
2 answers:
lesantik [10]3 years ago
8 0

Answer:

D. -170 kJ (apex)

tankabanditka [31]3 years ago
6 0
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S

Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol

If we take a basis of 1 mol, the answer is
D. -170 kJ 
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ch4aika [34]

Answer:

Ver explicacion

Explanation:

Cuando el cilindro de 40 libras está conectado al cilindro de 100 libras, generamos una presión que continúa hasta que los dos cilindros alcanzan la misma presión de gas en equilibrio. Recuerde que el cilindro de 100 libras estaba inicialmente vacío. Esto significa que su presión inicial es 0. El cilindro de 40 libras ya estaba lleno, por lo que dividimos esta cantidad en dos para tener en cuenta su distribución entre los dos cilindros.

Ahora tenemos 20 libras de gas propano presentes en cada cilindro. La implicación de esto es que, en el cilindro de 100 libras, necesitamos 80 libras adicionales para completar las 100 libras.

5 0
2 years ago
The charges of a set of isoelectronic ions vary from 3+ to 3-. Place the ions in order of increasing size.
ser-zykov [4K]

Answer:

Explanation:

  Iso-electronic species have same number of electrons . Positive charged ions will have smaller size . As electrons add , size increases due to electronic repulsion .

Following species are isoelectronic .

Al³⁺ < Mg²⁺ < Na¹⁺ < Ne < F⁻¹ < O⁻² < N⁻³

4 0
3 years ago
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

8 0
2 years ago
1. Carson completed conductivity testing on the solutions shown in the data table below and recorded his findings in the conduct
pishuonlain [190]

Answer:

See below :)

Explanation:

There is an evident reason why some of the solutions Carson's has listed and observed, does conduct electricity and some that do.

A flow of electrical charge is called an electric current. Ions are atoms, or sets of atoms, that contain an electrical charge. There are two types of ions, cation or a positively charged ion containing a deficiency of electrons, and anion or a negatively charged ion which contains a surplus of electrons. When a solution conducts electricity the charge is carried within by ions that move through the solution. The larger the number of ions in the solution, the better the conductivity of the solution is. Pure water does not conduct very well because it contains very few ions, but when table salt (NaCl) is dissolved in the water, this solution does conduct well because the solution contains a more abundance of ions. The majority of the ions come from the table salt, chemically names sodium chloride. Because Sodium contains its sodium ions, and these are positive charge and chloride ions which is a negative charge, it is called an ionic substance. Not every substance is made up of ions, one such example is sugar (C12H22O11). Sugar is made up of uncharged particles also called molecules. Although sugar is a substance its molecules do not hold a charge, thus when sugar is dissolved in water, the solution does not conduct electricity, due to the lack of ions in the solution.

Therefore, depending on the ions that make up the compound, the substance would or would not conduct electricity.

4 0
3 years ago
Tris {(hoch2)3cnh2} is one of the most common buffers used in biochemistry. a solution is prepared by adding enough tris and 12
shusha [124]

Given that,

The concentration of TRIS = 0.30 M

The concentration of TRIS+ = 0.60 M

Kb = 1.2 x 10^-6

pKb = -log Kb = - log (1.2 x 10^-6) = 5.920

Now, by using the Hendersonn equation,

pH = pKa + log TRIS+/TRIS = 5.920 + log (0.60/0.30) = 6.221

<span>pOH=14-pH=14-6.221 = 7.779</span>

7 0
3 years ago
Read 2 more answers
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