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2 years ago

5

How much heat energy is required to raise the temperature of 50g of bromine from 25°C to 30°C? [Specific heat capacity of bromin

e = 0.226 J/(g°C]

1 answer:

Elza [17]2 years ago

7 0

Answer: 56.5 J

Explanation:

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You need to make an aqueous solution of 0.215 M aluminum bromide for an experiment in lab, using a 300 mL volumetric flask. How

Karo-lina-s [1.5K]

Answer:

We have to add 17.2 grams of aluminium bromide

Explanation:

Step 1: Data given

Molarity of the aluminum bromide solution = 0.215 M

Volume = 300 mL = 0.300 L

Molar mass aluminium bromide = 266.69 g/mol

Step 2: Calculate moles Aluminium bromide

moles AlBr3 = volume * molarity

Moles AlBr3 = 0.300 L * 0.215 M

Moles AlBR3 = 0.0645 moles

Step 3: Calculate mass aluminium bromide

Mass aluminium bromide = moles AlBr3 * molar mass AlBr3

Mass aluminium bromide = 0.0645 moles * 266.69 g/mol

Mass aluminium bromide = 17.2 grams

We have to add 17.2 grams of aluminium bromide

3 0

3 years ago

Help pleaseeeeee. dbdb

maks197457 [2]

Answer:

no way

Explanation:

more free points

3 0

3 years ago

A 20.00-ml sample of 0.3000 m hbr is titrated with 0.15 m naoh. what is the ph of the solution after 40.3 ml of naoh have been a

Zielflug [23.3K]

$Molarity = no.of moles/vol.of the solution$

Then, $no.of moles of NaOH= 0.15M*40.3ml$

$= 6.04510x^{-3} moles$

$no.of moles of HCl= 0.30M×20ml= 6.010^-3 moles$

The reaction is as bellows:

$HCl+NaOH= NaCl+H2O$

1 mole $HCl$ reacts with 1 mole $NaOH$

Therefore, $6.0 × 10^- .. 6.0 × 10 ^-3 moles of NaOH$

Then, unreacted $NaOH= (6.045×10^-3–6.0×10^-3) moles$

$= 4.5×10^-5 moles$

Volume of the solution = $(20+40.3)ml= 60.3ml= 6.03×10–2 L$

Now, molar concentration of $NaOH= 4.5×10^-5 moles/6.03×10^-2L$

$= 7.46×10–4 moles/L$

$NaOH$ completely dissociates in solution.

Therefore, $[NaOH]=[[OH-]=7.46×10^-4 moles/L$

$pOH= -log[OH-]= -log(7.46×10^-4)= 3.12$

Again, $pH+pOH=14$

or, $pH=14-pOH$

$= 14–3.12= 10.88$

<h3> </h3><h3>If sodium hydroxide were added to a solution of strong acid, what would happen to the pH of the solution?</h3>

Depending on how much $NaOH$ is added, yes. The solution has a pH of 7 if the amount of additional $NaOH$ is exactly equal to the amount of acid.

Since $NaOH$ is an excess reagent, the solution will become basic if more equivalents of base are added than equivalents of acid, and the pH of the solution will rise above 7.

The solution will be acidic, with a pH lower than 7, if the number of equivalents of acid exceeds that of the $NaOH$ that has been added.

To learn more about Sodium hydroxide,visit:

brainly.com/question/20371039

#SPJ4

8 0

2 years ago

Mixtures are classified as homogeneous and heterogeneous according to _____.

kicyunya [14]

Mixtures are classified as homogeneous and heterogeneous according to the distribution of the components of the mixture. If the components are uniformly distributed in the mixture resulting to uniform properties, then it is a homogeneous mixture. However, if it is not uniformly distributed where the composition of one part of the mixture is not the same as other parts, then it is classified as an homogeneous mixture.

5 0

3 years ago

Read 2 more answers

How many grams of molybdenum (Mo) are in 2.68E24 atoms of Mo?

Margarita [4]

Answer:

427.1g Mo

Explanation:

use stoichiometry to get from atoms of Mo to moles of Mo to mass of Mo.

8 0

3 years ago