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Nimfa-mama [501]
3 years ago
12

You need to make an aqueous solution of 0.215 M aluminum bromide for an experiment in lab, using a 300 mL volumetric flask. How

much solid aluminum bromide should you add
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

We have to add 17.2 grams of aluminium bromide

Explanation:

Step 1: Data given

Molarity of the aluminum bromide solution = 0.215 M

Volume = 300 mL = 0.300 L

Molar mass aluminium bromide = 266.69 g/mol

Step 2: Calculate moles Aluminium bromide

moles AlBr3 = volume * molarity

Moles AlBr3 = 0.300 L * 0.215 M

Moles AlBR3 = 0.0645 moles

Step 3: Calculate mass aluminium bromide

Mass aluminium bromide = moles AlBr3 * molar mass AlBr3

Mass aluminium bromide = 0.0645 moles * 266.69 g/mol

Mass aluminium bromide = 17.2 grams

We have to add 17.2 grams of aluminium bromide

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Answer:

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.

This is illustrated below:

From the balanced equation above,

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