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Harrizon [31]
2 years ago
8

A series of concrete pillars have been built on the border between Kuwait and Iraq. They are there to __________ the border.

Engineering
1 answer:
Gala2k [10]2 years ago
5 0

A series of concrete pillars have been built on the border between Kuwait and Iraq. They are there to demarcate the border.

<h3>What is a border?</h3>

A border is a geographical boundary that separate<em> countries, states, provinces, counties, cities, and towns.</em>

A series of concrete pillars have been built on the border between Kuwait and Iraq. They are there to demarcate the border.

Find out more on border at: brainly.com/question/811755

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Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output tho
Likurg_2 [28]

Answer:

See explanation

Explanation:

//Include the

//required header files.

#include <stdio.h>

//Define the

//main() function.

int main(void) {

//Declare the

//required variables.

char input_char;

int input_int;

double input_double;

char input_string[100];

//Prompt the user

//to enter an integer.

printf("Enter integer: ");

//Read and store

//the integer.

scanf("%d", &input_int);

//Prompt the user

//to enter a double value.

printf("Enter double: ");

//Read and store

//the double value.

scanf("%lf", &input_double);

//Prompt the user

//to enter a character.

printf("Enter character: ");

//Read and store

//the character.

scanf(" %c", &input_char);

//Prompt user to

//enter the string

printf("Enter string: ");

//Read and

//store the string.

scanf("%s", input_string);

//(1)

//Display the values.

printf("%d %lf %c %s\n",

input_int, input_double,

input_char, input_string);

//(2)

//Display the values

//in reverse order.

printf("%s %c %lf %d\n",

input_string, input_char,

input_double, input_int);

//(3)

//Cast the double to

//an integer and display it.

printf("%lf cast to an integer is %d",

input_double, (int)(input_double));

//Return from the

//main() function.

return 0;

}

4 0
3 years ago
Copper spheres of 20-mm diameter are quenched by being dropped into a tank of water that is maintained at 280 K . The spheres ma
Ivenika [448]

Answer:

The height of the water is 1.25 m

Explanation:

copper properties are:

Kc=385 W/mK

D=20x10^-3 m

gc=8960 kg/m^3

Cp=385 J/kg*K

R=10x10^-3 m

Water properties at 280 K

pw=1000 kg/m^3

Kw=0.582

v=0.1247x10^-6 m^2/s

The drag force is:

F_{D} =\frac{1}{2} Co*p_{w} A*V^{2}

The bouyancy force is:

F_{B} =V*p_{w} *g

The weight is:

W=V*p_{c} *g

Laminar flow:

v_{T} =\frac{p_{c}-p_{w}*g*D^{2}   }{18*u} =\frac{(8960-1000)*9.8*(20x10^{-3})^{2}  }{18*0.00143} =1213.48 m/s

Reynold number:

Re=\frac{1000*1213.48*20x10^{-3} }{0.00143} \\Re>>1

Not flow region

For Newton flow region:

v_{T} =1.75\sqrt{(\frac{p_{c}-p_{w}  }{p_{w} })gD }=1.75\sqrt{(\frac{8960-1000}{1000} )*9.8*20x10^{-3} }  =2.186m/s

Re=\frac{1000*2.186*20x10^{-3} }{0.00143} =30573.4

Pr=\frac{\frac{u}{p} }{\frac{K}{pC_{p} } } =\frac{u*C_{p} }{k} =\frac{0.0014394198}{0.582} =10.31

Nu=2+(0.4Re^{1/2} +0.06Re^{2/3} )Pr^{2/5} (u/us)^{1/4} \\Nu=2+(0.4*30573.4^{1/2}+0.06*30573.4^{2/3}  )*10.31^{2/5} *(0.00143/0.00032)^{1/4} \\Nu=476.99

Nu=\frac{h*d}{K_{w} } \\h=\frac{476.99*0.582}{20x10^{-3} } =13880.44W/m^{2} K

\frac{T-T_{c} }{T_{w}-T_{c}  } =e^{-t/T} \\T=\frac{m_{c}C_{p}  }{hA_{c} } =\frac{8960*10x10^{-3}*385 }{13880.44*3} =0.828 s

e^{-t/0.828} =\frac{320-280}{360-280} \\t=0.573\\heightofthewater=2.186*0.573=1.25m

8 0
3 years ago
a ten station assembly machine has ideal cycle time of 6 sec. the fraction defect rate at each station 0.005 and defect always j
MAXImum [283]

Answer:

T_{P}=(2.6667)(10^{-3})h

Explanation:

Let's write the equation of the production rate for the assembly machine :

T_{P}=T_{C}+(n).(m).(p).(T_{D})

Where T_{P} is the production rate for the assembly machine.

Where T_{C} is the ideal cycle time

Where n is the number of stations.

Where m is the number stations that get jam when the defect occurs.

Where p is the defect rate at each station.

And where T_{D} is the average downtime per breakdown

We are looking for the hourly production rate ⇒

1h=60min\\1min=60s ⇒

1h=3600s ⇒

6s=\frac{(6s)(1h)}{(3600s)}= \frac{1}{600}h

60min=1h ⇒

1.2min=\frac{(1.2min)(1h)}{(60min)}=0.02h

T_{P}=\frac{1}{600}h+(10)(1.0)(0.005)(0.02h)=\frac{1}{375}h=(2.6667)(10^{-3})h

m = 1.0 in the equation.

3 0
3 years ago
What are the three categories of tools?
noname [10]

Answer:

1.      Low power hand tools/small

2.     Light to medium industrial tools

3.     Large industrial tools

There are definitely a lot more categories than three, but this is what I have.

6 0
3 years ago
Column arrays: Transpose a row array Construct a row array countValues with elements 1 to endValue, using the double colon opera
White raven [17]

Answer:

Matlab code with step by step explanation and output results are given below

Explanation:

We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).  

function countValues = CreateArray(endValue)

% Here we construct a row vector countValues from 1:endValue

     countValues = 1:endValue;

% then we transpose this row vector into column vector

     countValues = countValues';

 end

Output:

Calling this function with the endValue=11 returns following output

CreateArray(11)

ans =

    1

    2

    3

    4

    5

    6

    7

    8

    9

   10

   11

Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.

7 0
3 years ago
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