Answer:
a)W=12.62 kJ/mol
b)W=12.59 kJ/mol
Explanation:
At T = 100 °C the second and third virial coefficients are
B = -242.5 cm^3 mol^-1
C = 25200 cm^6 mo1^-2
Now according isothermal work of one mole methyl gas is
W=-
a=
b=
from virial equation
And
a=
b=
Now calculate V1 and V2 at given condition
Substitute given values 
= 1 x 10^5 , T = 373.15 and given values of coefficients we get
Solve for V1 by iterative or alternative cubic equation solver we get
Similarly solve for state 2 at P2 = 50 bar we get
Now
a=241.33
b=30780
After performing integration we get work done on the system is
W=12.62 kJ/mol
(b) for Z = 1 + B' P +C' P^2 = PV/RT by performing differential we get
dV=RT(-1/p^2+0+C')dP
Hence work done on the system is
a=
b=
by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work
W=12.59 kJ/mol
The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series
Answer:
Divide the difference in tax by the amount of income from the investment, and you'll get the economic marginal tax rate from investing. Most people refer to marginal tax rates as being identical to tax brackets.
hope this helps
have a good day :)
Explanation:
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
#include<iostream>
using namespace std;
int main ()
{
// Variable declaration
string name;
int numQuestions;
int numCorrect;
double percentage;
//Prompt to enter student's first and last name
cout<<"Enter student's first and last name";
cin>>name; // this line accepts input for variable name
cout<<"Number of question on test"; //Prompt to enter number of questions on test
cin>> numQuestions; //This line accepts Input for Variable numQuestions
cout<<"Number of answers student got correct: "; // Prompt to enter number of correct answers
cin>>numCorrect; //Enter number of correct answers
percentage = numCorrect * 100 / numQuestions; // calculate percentage
cout<<name<<" "<<percentage<<"%"; // print
return 0;
}
Explanation:
The code above calculates the percentage of a student's score in a certain test.
The code is extracted from the Question and completed after extraction.
It's written in C++ programming language
Answer:
18 kJ
Explanation:
Given:
Initial volume of air = 0.05 m³
Initial pressure = 60 kPa
Final volume = 0.2 m³
Final pressure = 180 kPa
Now,
the Work done by air will be calculated as:
Work Done = Average pressure × Change in volume
thus,
Average pressure = 
= 120 kPa
and,
Change in volume = Final volume - Initial Volume = 0.2 - 0.05 = 0.15 m³
Therefore,
the work done = 120 × 0.15 = 18 kJ
