Question

What is the output of a system with the transfer function s/(s + 3)^2 and subject to a unit step input at time t = 0?

Answer 1

Answer:

0

Explanation:

output =transfer function H(s) ×input U(s)

here H(s)=$\frac{s}{(s+3)^2}$

U(s)=$\frac{1}{s}$ for unit step function

output =H(s)×U(s)

=$\frac{s}{(s+3)^2}$×$\frac{1}{s}$

=$\frac{1}{(s+3)^2}$

taking inverse laplace of output

output=t×$e^{-3t}$

at t=0 putting the value of t=0 in output

output =0