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3 years ago

Multiply and divide rational expressions and simplify the answer

Mathematics

1 answer:

lord [1]3 years ago

7 0

Answer:

1. 32x/15

2. 2/x-4

3. 1/10x+10

4. 3x^6/5x^9

5. (x-3)(x-9)/6

6. x^2/3

Step-by-step explanation:

multiply the Numerator with the Numerator of other number and multiply the denominator of the first with the denominator of the second. Find a common factor in both the Numerator and denominator to be able to cross out the identical factors.

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you are working on a project for school. the project will take 12 hours to finish in all. so far, you have worked on the project

nasty-shy [4]

Answer:

6 hours and 45 minutes

Step-by-step explanation:

First, convert 12 hours into minutes.

12*60=720

Convert 5 hours to minutes and add 15

5*60=300+15=315

Subtract 720 from 315.

720-315=405

Convert into hours and minutes.

405/60=6.75

0.75 of an hour is 45 minutes so the answer is 6 hours and 45 minutes.

7 0

3 years ago

Solve the inequality.

77julia77 [94]

42 < -6d

divide 6 by both sides,

7 < -d

6 0

3 years ago

How can you use unit rates to make comparisons

Firlakuza [10]

Equivalent rates can be used to compare different sets of quantities that have the same value. A rate that compares a quantity to one is called a unit rate. The unit rate has a denominator equal to one when written as a fraction. Unit rates can be used to find larger equivalent rates.

5 0

4 years ago

Nan buys a greeting card for 2 dollars and 29 cents. She pays with three $1 bills.

Alexandra [31]

Answer:

71 cents

Step-by-step explanation:

7 0

3 years ago

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

Natasha2012 [34]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the 9% confidence interval is given by:

$8.8104 \leq \mu \leq 11.1248$

We can calculate the mean with the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

And we can find the margin of error with:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this case is given by:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

And we can solve for the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for 95% confidence using the normal standard distribution is approximately 1.96 and replacing we got:

$SE = \frac{1.1572}{1.96}= 0.5904$

Now for the 98% confidence interval the significance is $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ the critical value would be 2.326 and then the confidence interval would be:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

8 0

3 years ago