So first one
'how many solutions does 2x-y=-5 and 2x+y=5 have?'
add and get
2x-y-5
plus
2x+y=5
equals
2x+2x+y-y=5-5
4x=0
x=0 always
solve for y
4(0)+y=5
y=5
the solution is (0,5)
only <u>ONE </u>solution
one way is to subsitute
just remember that it is in (x,y) form so
the pont (1,2) means that 1 solution is x=1 and y=2 so subsitute and find that
the first one is the answer you are correct
just look at the graph
the solution is the intersection
it seems to be at a point that is 3 units to the right and -6 units up (6 units down)
so the solution is (3,-6)
yo are corect
subsitution
y=y
therefor
the answe ris (-4,-14) if you did the math correctly
#8 is correct
# 9 is correct
# 10 the answe ris bananas=0.40 pears=0.60
the last one you got it wrong, remember to check your answer to the graph for commonsense
then answer is (-2,5) and (1,2)
The area to the right of z = 1.35 is 0.0885 and the area to the left of -0.47 is 0.3192.
<h3>How to compute the values?.</h3>
Given z = 1.35
= 1- P(z < 1.35)
= 1- 0.9115
= 0.0885
The area to the left of -0.47 will be:
= 1 - P(z < 0.47)
= 1 - 0.6808
= 0.3192
Learn more about normal curve on:
brainly.com/question/6758792
#SPJ1
The solution to that equation is (6,-4)
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
