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finlep [7]
3 years ago
7

Find three consecutive integers such that three times the sum of the first two is eight more than 5 times the third.

Mathematics
1 answer:
klasskru [66]3 years ago
7 0
Consecutive integers are numbers one after the other on the number one (ie. 1,2,3,4,5 or 203,204,205).

times= multiplication
sum= addition
more than= addition
is= equal sign

x= first integer
x+2= second integer
x+3= third integer

3(x + (x + 2))= 5(x + 3) + 8
add inside parentheses

3(2x + 2)= 5(x + 3) + 8
multiply 3 and 5 by their parentheses

(3*2x) + (3*2)= (5*x) + (5*3) + 8
multiply in parentheses

6x + 6= 5x + 15 + 8

6x + 6= 5x + 23
subtract 5x from both sides

x + 6= 23
subtract 6 from both sides

x= 17 first integer

x + 1= 17 + 1= 18 second integer

x + 2= 17 + 2= 19 third integer


CHECK:
3(x + (x + 2))= 5(x + 3) + 8
3(17 + (17 + 2))= 5(17 + 3) + 8
3(17 + 19)= 5(20) + 8
3(36)= 100 + 8
108= 108


ANSWER: The three consecutive integers are 17, 18 and 19.

Hope this helps! :)
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<h3>What is Equation?</h3>

An equation is a mathematical statement with an 'equal to =' symbol between two expressions that have equal values.

Here, As given in question

The number of gallons of gas Connie’s car, g, uses is directly proportional with the number of miles she drives, m.

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