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AleksAgata [21]
2 years ago
10

A sequence of patterns is made from circular tiles and square tiles. Here are the first three patterns in the sequence: a) How m

any square tiles are needed to make Pattern Number 7? [2 MARKS] b) How many circular tiles are needed to make Pattern Number 20? [2 MARKS] c) When the pattern number is odd, the total number of tiles (SQUARE & CIRCULAR) needed to make the pattern: A - will always be even | B - will always be odd | C - could be even or odd | [2 MARKS] !! PLEASE ANSWER ALL OF THE QUESTIONS !!
Mathematics
1 answer:
Citrus2011 [14]2 years ago
8 0

The patterns of tiles do not follow an arithmetic sequence or geometric sequence

When the pattern number is odd, the total number of tiles (SQUARE & CIRCULAR) needed to make the pattern will always be odd

<h3>The square tiles needed to make Pattern Number 7? </h3>

From the question, we have the following pattern:

  • Pattern 1: 1 square and 8 circles
  • Pattern 2: 4 squares and 12 circles
  • Pattern 3: 9 squares and 16 circles

The number of square tiles is calculated using:

Tn= n²

So, we have:

T₇ = 7²

T₇ = 49

Hence, 49 square tiles are needed in pattern 7

<h3>The circular tiles needed to make Pattern Number 20</h3>

The number of circular tiles is calculated using:

Tn= 4n + 4

So, we have:

T₂₀= 4 * 20 + 4

T₂₀= 84

Hence, 84 circular tiles are needed in pattern 20

<h3>c) The conclusion on odd pattern number</h3>

Using the computations in (a) and (b), we have:

The total number of tiles in odd pattern number is always odd

Read more about pattern and sequence at:

brainly.com/question/7882626

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Answer:

\sigma = 11.28 --- Standard deviation

Step-by-step explanation:

Given

See attachment for graph

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\bar x = \frac{50 * 1 + 57 * 2 + 60 * 4 + 65 * 3 +72 *3 + 75 * 12 + 77 * 10 + 81 * 6 + 83 * 6 + 88 * 9 + 90 * 12 + 92 * 12 +95 * 2 + 99 * 4 + 100 * 5}{1 + 2 + 4 + 3 +3 + 12 + 10 + 6 + 6 + 9 + 12 + 12 +2 + 4 + 5}

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Next, calculate the variance using the following formula:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f}

i.e subtract the mean from each dataset; take the squares; add up the squares; then divide the sum by the number of dataset

So, we have:

\sigma^2 = \frac{1 * (50 - 82.76)^2 +...................+ 5 * (100 - 82.76)^2}{91}

\sigma^2 = \frac{11580.6816}{91}

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\sigma = \sqrt{127.26}

\sigma = 11.28 --- approximated

<em>Hence, the standard deviation is approximately 11.28</em>

Considering the calculated mean (i.e. 82.76), the standard deviation (i.e. 11.28) is small and this means that the grade of the students are close to the average grade.

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