let's recall the remainder theorem.
we know that (x-1) is a factor, that means x -1 = 0 or x = 1.
since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.
![f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k](https://tex.z-dn.net/?f=f%28x%29%3D3x%5E3%2Bkx-11%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C%5Cstackrel%7B0%7D%7Bf%281%29%7D%3D3%281%29%5E3%2Bk%281%29-11%5Cimplies%20%5Cstackrel%7Bf%281%29%7D%7B0%7D%3D3%2Bk-11%5Cimplies%200%3D-8%2Bk%5Cimplies%208%3Dk)
Okay so.
2/5=24/60 (multiply 2/5 by 12)
2/3=40/60 (multiply 2/3 by 20)
1/4=15/60 (multiply 1/4 by 15)
Then,
Add 24/60 with 40/60 which is 64/60 after you get that you subtract by 15/60 and you get 49/60.
Hope this helps!^^
Answer:
27
Step-by-step explanation:
Answer:
1/-2
Step-by-step explanation:
To find the slope:
rise/run
From point to point
So....
From (-1,0)
you go up 2(2)
then left 4(-4)
to get to (-5,2)
so 2/-4 reduced is 1/-2
<u>We are given:</u>
An even number 'n', multiplied by the next consecutive even number is 168
<u>Solving for n:</u>
From the given statement, we can say that:
n(n+2) = 168 [<em>n multiplied by the next even number 'n+2'</em>]
n² + 2n = 168
n² + 2n - 168 = 0 [<em>subtracting 168 from both sides</em>]
We can see that we now have a quadratic equation, solving using splitting the middle term
n² + 14n - 12n - 168 = 0
n(n + 14) -12(n + 14) = 0 <em>[factoring out common terms</em>]
(n-12)(n+14) = 0
Here, we can divide both sides by either (n-12) OR (n+14)
Checking the result in both the cases:
(n + 14) = 0/(n-12) (n-12) = 0/(n+14)
n + 14 = 0 n - 12 = 0
n = -14 n = 12
Both these values are even and since we are not told if the number 'n' is positive or negative, both 12 and -14 are the possible values of n
