[Given]
{ x + y = 6
{ x = y + 4
[Plug-in our x value & solve]
[Given] x + y = 6
[ Plug-in] (y + 4) + y = 6
[Distribute] y + 4 + y = 6
[Combine like terms] 2y + 4 = 6
[Subtract 4 from both sides] 2y = 2
[Divide both sides by 2] y = 1
[Answer]
Third option - (5, 1)
-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly
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- Heather
If Hannah gives her younger sister 3 shirts, it does not matter what order she hands them to her. No matter the order, it will still be the same group of 3 shirt. Since order is not important this problem can be solved using a combination.
Specifically we are asked to find 8C3 (sometimes called "8 choose 3"). This is a fraction. In the numerator we start with 8 and count down 3 numbers. In the denominator we start with 3 and count all the way down to 1. Thus we obtain,
Maybe, the price went down $20 eight times?
The answer should be -5x + 7y = -108
7 squared equals 7 times 7