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Orlov [11]
3 years ago
6

What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s^2)

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

None of these

Step-by-step explanation:

Normally, we consider "weight" to be the force due to gravity that an object exerts in the downward direction. It has a positive value equal to the magnitude of "mg". In this instance, it would be ...

... |(10 kg)·(-9.8 N/kg)| = |-98 N| = 98 N

___

However, you're specifically told to use ...

... w = mg

... w = (10 kg)(-9.8 m/s²) = -98 N

This selection is not among those offered.

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Please help please help
White raven [17]

Answer:

1/3

Step-by-step explanation:

A dilation is an enlargement or reduction of an image by a scale factor. The scale factor is the same ratio that cam be found from between the two figures.

The long leg of the original triangle has the length of 6. The small triangle has a long leg of length 2.

The ratio is 2/6 = 1/3.

5 0
3 years ago
PLEASE HELP ASAPP SHOW UR WORK i’ll mark brainliest!!
ASHA 777 [7]

Answer:

c = 15n + 50

Step-by-step explanation:

the total cost = $15 for each person ( n ) + a $50 flat fee

6 0
3 years ago
Marcy played the piano for 45 minutes.She stopped playing at 4:15 P.M.At what time did she start playing the piano
musickatia [10]
15-45=-30
60-30=30
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3 0
3 years ago
Write the explicit form of the arithmetic sequence shown below:<br> -4, 3, 10, ...
Vinil7 [7]

Answer:

17

Step-by-step explanation:

_4 to +3 = 7

3 to 10 =7

thus the sequence is 7

the answer is 10+7=17

7 0
3 years ago
Find all zeros x^3+2x^2+4x+21
dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

\frac{x^3+2x^2+4x+21}{x+3} = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± \sqrt{1-28} ) / 2 = (1 ± 3i\sqrt{3} ) / 2

x = \frac{1}{2} ± \frac{3i\sqrt{3} }{2}

zeros are x = - 3, x = \frac{1}{2} ±\frac{3i\sqrt{3} }{2}


5 0
3 years ago
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