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Orlov [11]
3 years ago
6

What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s^2)

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

None of these

Step-by-step explanation:

Normally, we consider "weight" to be the force due to gravity that an object exerts in the downward direction. It has a positive value equal to the magnitude of "mg". In this instance, it would be ...

... |(10 kg)·(-9.8 N/kg)| = |-98 N| = 98 N

___

However, you're specifically told to use ...

... w = mg

... w = (10 kg)(-9.8 m/s²) = -98 N

This selection is not among those offered.

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F(-4)=8 and f(-1)=4 write the linear equation
kobusy [5.1K]

f(-4)=8\to(-4,\ 8)\\\\f(-1)=4\to(-1,\ 4)

The point-slope formula of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute:

m=\dfrac{4-8}{-1-(-4)}=\dfrac{-4}{3}=-\dfrac{4}{3}\\\\y-8=-\dfrac{4}{3}(x-(-4))\\\\y-8=-\dfrac{4}{3}x-\dfrac{16}{3}\ \ \ \ |+8\\\\y=-\dfrac{4}{3}x-\dfrac{16}{3}+\dfrac{24}{3}\\\\y=-\dfrac{4}{3}x+\dfrac{8}{3}\ \ \ |\cdot3\\\\3y=-4x+8\ \ \ |+4x\\\\4x+3y=8

The slope-intercept form: y=-\dfrac{4}{3}x+\dfrac{8}{3}

The standard form: 4x+3y=8


7 0
3 years ago
The Greek method for finding the equation of the tangent line to a circle uses the fact that at any point on the circle the line
Alina [70]

Answer:

Step-by-step explanation:

Given circle has equation as

x^2+y^2 =49

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The point of contact of tangent = (1,4\sqrt{3} )Q

Since tangent is perpendicular to the radius at the point of contact, we have

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We have point on this line as given point

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3 0
3 years ago
Consider △ABC.
VashaNatasha [74]

Answers:

∠A=45° & ∠B=45°

Step-by-step explanation:

In triangle ABC, all angles are less than 180° but their sum is 180°

For the trigonometric statements  

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sin(B)=cos(A)

These are true when these angles that are A and B are equal and on these angles the sin and cos value must be same.

Hence, both angles are of 45°




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Volume = length x width x height

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3 years ago
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