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marin [14]
3 years ago
11

X/6 = 10/9 improper fraction in its simplified form

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

\frac{x}{6}  =  \frac{10}{9}  \\   \therefore \: 9 \times x = 6 \times 10 \\ \therefore \:9x = 60 \\ \therefore \:x =  \frac{60}{9}  \\ \therefore \:x =  \frac{20}{3}  \\   \:  \:  \:  \:  \:  \: \huge \red{ \boxed{\therefore \:x =  6\frac{2}{3} }}

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The linear regression equation that represents  the set of data is:

y=1083.48+23.73x

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Step-by-step explanation:

The general form of a linear regression is:

y=a+bx

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>a</em> = intercept

<em>b</em> = slope

Compute the values of <em>a</em> and <em>b</em> as follows:

\begin{aligned}        a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 6857 \cdot 55 - 15 \cdot 17558}{ 6 \cdot 55 - 15^2} \approx 1083.476 \\ \\b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 17558 - 15 \cdot 6857 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 23.743\end{aligned}

The linear regression equation that represents  the set of data is:

y=1083.48+23.73x

Compute the predicted value of the number of new cases for 2013 (i.e. <em>x</em> = 12) as follows:

y=1083.48+23.73x

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Thus, the predicted number of new cases for 2013 is 1368.

8 0
3 years ago
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