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marin [14]
3 years ago
11

X/6 = 10/9 improper fraction in its simplified form

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

\frac{x}{6}  =  \frac{10}{9}  \\   \therefore \: 9 \times x = 6 \times 10 \\ \therefore \:9x = 60 \\ \therefore \:x =  \frac{60}{9}  \\ \therefore \:x =  \frac{20}{3}  \\   \:  \:  \:  \:  \:  \: \huge \red{ \boxed{\therefore \:x =  6\frac{2}{3} }}

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The pairs of integer having two real solution forax^{2} -6x+c = 0 are

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Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

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The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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