Water cannot be suctioned higher than 10.4 m because at that point

The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m

Molodets [167]

Answer:

r = 5.335 meters

Explanation:

Given that,

Charge 1, $q_1=-165\ \mu C$

Charge 2, $q_2=115\ \mu C$

Force of attraction between two charges, F = 6 N

The force of attraction between two charges is given by :

$F=k\dfrac{q_1q_2}{r^2}$ , r is the separation between two charges

$r=\sqrt{\dfrac{kq_1q_2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times 165\times 10^{-6}\times 115\times 10^{-6}}{6}}$

r = 5.335 m

So, the separation between two charges is 5.335 meters. Hence, this is the required solution.

6 0

3 years ago

Physics class 9 chapter 8 please tell please

natali 33 [55]

Answer:

(a) The motion is uniform

(b) 11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

Speed(s) = Δd/Δt

s = Δd/Δt............. Equation 1

From the table,

Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds

Substitute these values into equation 1

s = 10000/900

s = 11.11 m/s

7 0

3 years ago

A block of mass m1 = 290 g is at rest on a plane that makes an angle θ = 30° above the horizontal. The coefficient of kinetic fr

GrogVix [38]

Answer:

The speed of the block when is fallen 30cm

v=0.726 $\frac{m}{s}$

Explanation:

∑F= (m2)g - ƒ - (m1)g*sin(θ) = (m1)a

g = 9.81 m/s²

ƒ = μN = μ(m1)g

$(m2)*g - u*(m1)*g - (m1)*g*sin(\alpha ) = (m1)*a$

(0.200)(9.81) - (0.1)(0.290)(9.81) - (0.290)(9.81)sin(30°) = (0.290)a

$(0.200kg)(9.81\frac{m}{s^{2}}) - (0.1)(0.290kg)(9.81\frac{m}{s^{2}}) - (0.290kg)(9.81\frac{m}{s^{2}})sin(30°) = (0.290kg)*a$

$0.511101=0.29*a\\a=0.879\frac{m}{s^{2} }$

$v_{f}^{2}=v_{o}^{2}+2*a(x_{f}^{2}-v_{o}^{2})\\v_{o}=0\\v_{o}=0\\v_{f}^{2}=2*a(x_{f})\\v_{f}=\sqrt{2*a(x_{f})}\\v_{f}=\sqrt{2*0.879\frac{m}{s^{2}}*0.30m} \\v_{f}=0.726 \frac{m}{s}$

5 0

4 years ago

Can all rocks be weathered and eroded?how do you know?

skelet666 [1.2K]

Answer:yes

Explanation: Rock can be weathered by ice, acids, animals, temp and etc because the breaking down or dissolving of rock and minerals on the earths surface.

rocks can be eroded by wind, water, ice and, gravity be cause of an action, and friction.

(I think going off of what i learned.)

8 0

3 years ago

Read 2 more answers

A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=Lacross a horizontal surfac

Tomtit [17]

Answer:

A) v = √[(F₀/m - μ₀) 2x + x2 / L] , b) v = √[2 (F₀ / m - μ₀) +1] L

Explanation:

For this exercise we will use Newton's second law

X axis

Fo - fr = ma

Y Axis

N - W = 0

N = mg

The equation for the force of friction is

fr = μ N

.fr = μ mg

Let's replace

Fo - μ mg = m a

a = Fo / m - μ g

They ask us the speed of the block, so we must use

a = dv / dt = dv/dx dx dt = dv/dx v

v dv = a dx

We replace

v dv = (F₀ / m - μ₀ (1- x/L)) dx

We integrate

∫v dv = F₀ / m ∫ dx - μ₀ ∫ dx + 1 / L ∫ x dx

½ v² = (F₀ / m - μ₀) x + 1 / L x² / 2

We evaluate from the lower limit, for x = 0 the speed is zero v = 0, to the upper limit x, v

½ v² = (F₀ / m - μ₀) x + 1 / 2L x²

v = √[(F₀ / m - μ₀) 2x + x2 / L]

Part B

The velocity for x = L

v = √(F₀ / m - μ₀) 2L + L2 / L

v = √[2 (F₀ / m - μ₀) +1] L

8 0

3 years ago