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vesna_86 [32]
3 years ago
11

How far will a skateboard travel in 30 seconds if traveling at a speed of 3 m/s​

Physics
2 answers:
Grace [21]3 years ago
5 0
If it’s traveling at 3 miles per second, then you would do 3 times 30 and get 90.
Answer: it will travel 90 miles in 30 seconds
poizon [28]3 years ago
3 0
If it is 3m/s and it travels for 30 seconds, you multiply 3/30 to get 90m
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When does sea breeze occur
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3 0
4 years ago
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Acceleration due to gravity on earth is:
Olenka [21]
C because gravity is holding everything down
5 0
3 years ago
A dentist’s drill starts from rest. After 3.20 s of constant angu-lar acceleration, it turns at a rate of 2.51 3 104 re v/m i n.
Gekata [30.6K]

Answer:

ΔTita = 4205.6 rad

Explanation:

w_{i} means initial angular velocity, which is 0 rev/min

w_{f} means final angular velocity, which is 2.513*10^{4}rev/min

t means time t= 3.20 s

one revolution is equivalent to 2πrad so the final angular velocity is:

w_{f} = (2π/60) *2.513*10^{4} rad/s

w_{f}= 2628.5 rad/s

so the angular acceleration, α will be:

α = 2628.5 rad/s / 3.20 s

a = 821.40 rad/s^{2}

so the rotational motion about a fixed axis is:

w^{2} _{f} =w^{2} _{i} + 2αΔTita    where ΔTita is the angle in radians

so now find the ΔTita the subject of the formula

ΔTita = \frac{w^{2} _{f}-w^{2} _{i}  }{2a}

ΔTita = ((2628.5)^{2} - (0 rev/min)^{2}) / 2* 821.40

ΔTita = 4205.6 rad

7 0
4 years ago
Read 2 more answers
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
frez [133]

Answer:

<em>1.49 x </em>10^{11}<em></em>

<em></em>

Explanation:

Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>

Mathematically, this can be stated as

T^{2} ∝ R^{3}

<em>to remove the proportionality sign we introduce a constant</em>

T^{2} = kR^{3}

k = \frac{T^{2} }{R^{3} }

Where T is the orbital period,

and R is the orbit around the sun.

For mars,

T = 687 days

R = 2.279 x 10^{11}

for mars, constant k will be

k = \frac{687^{2} }{(2.279*10^{11}) ^{3} } = 3.987 x 10^{-29}

For Earth, orbital period T is 365 days, therefore

365^{2} = 3.987 x 10^{-29} x R^{3}

R^{3} = 3.34 x 10^{33}

R =<em> 1.49 x </em>10^{11}<em></em>

8 0
3 years ago
Read 2 more answers
If 7kg of onions costs 140 rupees then how much would we pay for 12kg of onions?
Rudik [331]

Answer:

240 rupees

Explanation:

As 7 kg of onions costs 140 rupees, each kg costs 20 rupees, and 12x20=240 rupees.

6 0
4 years ago
Read 2 more answers
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