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balandron [24]
1 year ago
14

Tyler is simplifying the expression 6 - 2x +

Mathematics
2 answers:
raketka [301]1 year ago
4 0

               - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\blue\textsf{\textbf{\underline{\underline{Question:-}}}}}\\\\\\\\\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}

Let's help Tyler simplify the expression correctly.

6-2x+5+4x

Add the x's:-

-2x+4x

2x

Now add the numbers:-

6+5

11

Put the terms together (but don't add them, since 11 and 2x are not like terms)

11+2x

An equivalent expression would be

2x+11 (switch the order)

<h3>Good luck.</h3>

   

                  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

user100 [1]1 year ago
3 0

Answer:

Tyler grouped up 6-2 and 5-4 instead of grouping up the x terms.

6-2x + 5+4x=

2x+4x= ?

6 + 5 = 11

11- 2x + 4x =

-2x + 4x = 2x

2x + 11

Step-by-step explanation:

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(-4,-6) and (3,-7) find the distance between each pair of points
Vlad [161]

Answer:

5\sqrt{2}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

(-4, -6), (3, -7)

x_{1} = -4

y_{1} =-6

x_{2} = 3

y_{2} =-7

so we have:

d =\sqrt{(3-(-4))^{2}+ (-7-(-6))^{2}}\\\\d =\sqrt{(7)^{2}+ (-1)^{2}}\\\\d = \sqrt{49+ 1}\\\\d=\sqrt{50}\\\\d=5\sqrt{2}

4 0
3 years ago
Read 2 more answers
There’s this one as well
Doss [256]

Answer:

V= area of cross-section x length

V = 0.5x(8x9) x 11

V = 396cm^3

Hope this helps!

6 0
2 years ago
Math Help Please explain the questions How long will it take for the balance of an account to double if the savings account earn
Scorpion4ik [409]
(See attached formula)
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 *  <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>

5 0
2 years ago
If the measure of the angle in the southwest corner of the intersection of Broadway and 21st Street is approximately 105ºwhat is
Karolina [17]

Answer:

95°

Step-by-step explanation:

The angle on the 20TH street and 22ND street must add up to 180° so the answer is 95°

5 0
3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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