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2 years ago

Tyler is simplifying the expression 6 - 2x +

Mathematics

2 answers:

raketka [301]2 years ago

4 0

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$\blue\textsf{\textbf{\underline{\underline{Question:-}}}}}\\\\\\\\\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}$

Let's help Tyler simplify the expression correctly.

6-2x+5+4x

Add the x's:-

-2x+4x

Now add the numbers:-

6+5

Put the terms together (but don't add them, since 11 and 2x are not like terms)

11+2x

An equivalent expression would be

2x+11 (switch the order)

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user100 [1]2 years ago

3 0

Answer:

Tyler grouped up 6-2 and 5-4 instead of grouping up the x terms.

6-2x + 5+4x=

2x+4x= ?

6 + 5 = 11

11- 2x + 4x =

-2x + 4x = 2x

2x + 11

Step-by-step explanation:

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Step-by-step explanation:

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so x=75 :)

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4 years ago

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- 12x +5y = 2<br> -3x+3y=-3

zlopas [31]

(3,2) is the answer of the system of equations.

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3 years ago

Given f(x)= 3x+2, what is the Inverse Function?

Grace [21]

Answer:

Step-by-step explanation:

For this case we must determine the inverse of the following function:

$f(x)=3x-2$

Step 1:

We would write

$y=f(x)$ or $y=3x-2$

Step 2:

We clear x:

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Step 3:

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3 years ago

Find the values of C for which C(x+2)—(x+2)(x–2)=0 has just one solution. please help me ASAP

CaHeK987 [17]

<h3>Answer: C = -4</h3>

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Work Shown:

C(x+2) - (x+2)(x-2) = 0

(x+2)(C-(x-2)) = 0

(x+2)(C-x+2) = 0

x+2 = 0 or C-x+2 = 0

x = -2 or x = C+2

If we want one solution only, then we must make C+2 = -2 which solves to C = -4

If C = -4, then x = C+2 = -4+2 = -2 which matches with the first solution mentioned. If C is anything else but -4, then we'd have two different solutions (eg: C = 10 leads to x = C+2 = 12 as the other solution)

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2 years ago

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

lubasha [3.4K]

Answer in order:

False

True

False

True

Step-by-step explanation:

All of the solutions to the equation $3x^2 - 12 = 0$ are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

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The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

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The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]

7 0

3 years ago