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balandron [24]
2 years ago
14

Tyler is simplifying the expression 6 - 2x +

Mathematics
2 answers:
raketka [301]2 years ago
4 0

               - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\blue\textsf{\textbf{\underline{\underline{Question:-}}}}}\\\\\\\\\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}

Let's help Tyler simplify the expression correctly.

6-2x+5+4x

Add the x's:-

-2x+4x

2x

Now add the numbers:-

6+5

11

Put the terms together (but don't add them, since 11 and 2x are not like terms)

11+2x

An equivalent expression would be

2x+11 (switch the order)

<h3>Good luck.</h3>

   

                  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

user100 [1]2 years ago
3 0

Answer:

Tyler grouped up 6-2 and 5-4 instead of grouping up the x terms.

6-2x + 5+4x=

2x+4x= ?

6 + 5 = 11

11- 2x + 4x =

-2x + 4x = 2x

2x + 11

Step-by-step explanation:

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Rainbow [258]

By algebra properties we find the following relationships between each pair of algebraic expressions:

  1. First equation: Case 4
  2. Second equation: Case 1
  3. Third equation: Case 2
  4. Fourth equation: Case 5
  5. Fifth equation: Case 3

<h3>How to determine pairs of equivalent equations</h3>

In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:

First equation

(7 - 2 · x) + (3 · x - 11)

(7 - 11) + (- 2 · x + 3 · x)

- 4 + (- 2 + 3) · x

- 4 + (1) · x

- 4 + (5 - 4) · x

- 4 - 4 · x + 5 · x

- 4 · (x + 1) + 5 · x → Case 4

Second equation

- 7 + 6 · x - 4 · x + 3

(6 · x - 4 · x) + (- 7 + 3)

(6 - 4) · x - 4

2 · x - 4

2 · (x - 2) → Case 1

Third equation

9 · x - 2 · (3 · x - 3)

9 · x - 6 · x + 6

3 · x + 6

(2 + 1) · x + (14 - 8)

[1 - (- 2)] · x + (14 - 8)

(x + 14) - (8 - 2 · x) → Case 2

Fourth equation

- 3 · x + 6 + 4 · x

x + 6

(5 - 4) · x + (7 - 1)

(7 + 5 · x) + (- 4 · x - 1) → Case 5

Fifth equation

- 2 · x + 9 + 5 · x  + 6

3 · x + 15

3 · (x + 5) → Case 3

To learn more on algebraic equations: brainly.com/question/24875240

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5 0
1 year ago
Please help!!!!!!!!!!!!!!!!!
Bas_tet [7]

Answer:

hi

Step-by-step explanation:

7 0
3 years ago
For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
viva [34]

Answer:

option C. -\frac{5}{13}

Step-by-step explanation:

we have  that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

cos(\theta)=-\frac{5}{13}

8 0
3 years ago
Which of the following is NOT a statistical question?
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D is not because you can not graph it.
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What is the solution for line one: y=-2x+1 line two: -2x-3
Oliga [24]

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x

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b

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\m

=

2

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=

−

3

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, and the y-intercept is the value of

b

.

Slope:

2

y-intercept:

(

0

,

−

3

)

Any line can be graphed using two points. Select two

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x-intercept(s):

(

3

2

,

0

)

Find the y-intercept.

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y-intercept(s):

(

0

,

−

3

)

Create a table of the

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and

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x

y

0

−

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3

2

0

m

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b

=

−

3

The slope of the line is the value of

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2

y-intercept:

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0

,

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values, and plug them into the equation to find the corresponding

y

values.

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Find the x-intercept.

Tap for more steps...

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(

3

2

,

0

)

Find the y-intercept.

Tap for more steps...

y-intercept(s):

(

0

,

−

3

)

Create a table of the

x

and

y

values.

x

y

0

−

3

3

2

0

I'm so sorry it layed out like this my computer is being st00pid

6 0
3 years ago
Read 2 more answers
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